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3 years ago

Of 15 possible books, you plan to take 6 with you on vacation. How many different collections of 6 books can you take?

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

6 0

Answer:

5005

Step-by-step explanation:

6 C 15

(6, 15)

15! / (6! x 9!)

The answer is 5005

C is just a way to say the order the books are picked in is random and ! means factorial. Factorial is when you multiply all the previous numbers up to the number it is. For example, 5! = 1 x 2 x 3 x 4 x 5 and 2! = 1 x 2

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How do i get the factor of 3p2-2p-5

tensa zangetsu [6.8K]

3p² - 2p - 5 = 0

3p² + 3p - 5p - 5 = 0

3p(p + 1) -5(p + 1) = 0

(3p - 5)(p + 1) = 0

p = 5/3 or -1

Hope this helps!

5 0

3 years ago

Read 2 more answers

Spent Withdrew, Down,Decrease all have negative values

musickatia [10]

True, all of them represent a negative number, for example:

You have $60 and you spent $10, the remaining money is:

$60-10=50$

Your savings are $1000 and you make a Withdrawal of $500:

$1000-500=500$

In other words for calculation purposes, they all have negative values

6 0

1 year ago

Is (-5, 6) a solution to y = 2x + 4 ?<br> I need an answer quickly, please

Fittoniya [83]

Answer:

(-5, 6) is not a solution.

Step-by-step explanation:

6=2(-5)+4

6=-10+4

-10+4=-6, not 6.

7 0

3 years ago

If she makes 2 more batches of batter how many cups of flour will be left?

WINSTONCH [101]

One cup of flour will be e left

5 0

3 years ago

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Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

3 years ago

Of 15 possible​ books, you plan to take 6 with you on vacation. How many different collections of 6 books can you​ take?

Of 15 possible books, you plan to take 6 with you on vacation. How many different collections of 6 books can you take?