Answer:
There are 5,586,853,480 different ways to select the jury.
Step-by-step explanation:
The order is not important.
For example, if we had sets of 2 elements
Tremaine and Tre'davious would be the same set as Tre'davious and Tremaine. So we use the combinations formula.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

In how many different ways can a jury of 12 people be randomly selected from a group of 40 people?
Here we have
.
So

There are 5,586,853,480 different ways to select the jury.
Answer:
35/27
Step-by-step explanation:
We simply need to divide the product of the numbers (-28/81) by one of the numbers (-4/15):

The second number is 35/27.
Answer:
Tn=T1+(n-1)*d
Step-by-step explanation:
Tn is the nth term
T1 is the first term of the sequence
n is the nth term as well
d is the common difference
Answer: the cost of an adult ticket is $9.
The cost of a child's ticket is $13
Step-by-step explanation:
Let x represent the price of one adult ticket.
Let y represent the price of one student ticket.
On the first day of ticket sales, the school sold two adult tickets and three students tickets for a total of $57. It means that
2x + 3y = 57- - - - - - - - - -1
The school took and $70 on the second day by selling two adult tickets and four student tickets. It means that
2x + 4y = 70- - - - - - - - - -2
Subtracting equation 2 from equation 1, it becomes
- y = - 13
y = 13
Substituting y = 13 into equation 1, it becomes
2x + 3 × 13 = 57
2x + 39 = 57
2x = 57 - 39 = 18
x = 18/2
x = 9