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xxTIMURxx [149]
3 years ago
9

Which two equations would be most appropriately solved by using the zero product property? Select each correct answer. 4x² = 13

0.25x2+0.8x−8=0 −(x−1)(x+9)=0 3x2−6x=0
Mathematics
2 answers:
olga55 [171]3 years ago
5 0
The zero product property tells us that if we multiply two quantities together and get zero, then one or both of these is equal to zero.

In symbols this means that if ab = 0 then a = 0, b = 0 or both.

This means that if we have a product equal to zero one of both of the factors (the things we are multiplying together) is equal to zero.

Of the equations given, the only one that has product (a few terms multiplied together) equal to zero is -(x-1)(x+9)=0 so this is the one that can most appropriately be solved by the zero product property.

We can re-write -(x-1)(x+9) = 0 as (-1)(x-1)(x+9) = 0 which means (x-1) or (x+9) or both equal zero. It should be clear that -1 cannot equal zero.

To solve we set x - 1 = 0 and obtain x = 1.
Next we set x + 9 = 0 and obtain x = -9

The solutions to the equation are x = -9 and x = 1.

We are, however, asked for two equations. Though none of the remaining equations has a product set equal to zero, we can re-write the equation 3 x^{2} -6x=0 by factoring 3x from each term on the left-hand side. Doing so gives us 3x(x-2)=0. Now we have a product equal to zero which means that one or both of the factors on the left-hand side equals zero.

That is, 3x equals 0, or x-2 equals 0 or both do. If 3x = 0 then x = 0. If x-2=0 then x=2. As such the solution to the equation is x = 0, x = 2.
netineya [11]3 years ago
5 0

Answer:

−(x−1)(x+9)=0

And..

3x2−6x=0

Step-by-step explanation:

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A triangle has a perimeter of 31. The longest side is equal to 12. The difference of the other two is 3. What is length of the s
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The perimeter is the sum of the 3 sides of the triangle.

let the other 2 sides be x and x - 3 , then

12 + x + x - 3 = 31

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what was the interest rate if your balance on an investment of 857 dollars at the end of six years is 1268.36 dollars​
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<h3>The interest rate is 8 % if your balance on an investment of 857 dollars at the end of six years is 1268.36 dollars​</h3>

<em><u>Solution:</u></em>

Given that,

Principal = $ 857

Amount = $ 1268.36

Number of years = 6

Rate of interest = ?

Simple Interest = Amount - principal

Simple Interest = 1268.36 - 857

Simple Interest = 411.36

<em><u>Use the formula,</u></em>

Simple Interest = \frac{ p \times n \times r}{100}\\\\411.36 = \frac{ 857 \times 6 \times r}{100}\\\\41136 = 5142 \times r\\\\r = \frac{41136}{5142}\\\\r = 8 \%

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3 0
3 years ago
Read 2 more answers
A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

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3 years ago
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