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lorasvet [3.4K]
3 years ago
13

Given the following sets.

Mathematics
1 answer:
vekshin13 years ago
4 0

Answer:

\large\boxed{e.\ \{a,\ b,\ c,\ d,\ 0,\ 2\}}

Step-by-step explanation:

\text{The union (denoted by}\ \cup\ \text{) of a collection of sets is the set of all elements of the sets. }\\\\A=\{0,\ 1,\ 2,\ 3\}\\\\B=\{a,\ b,\ c,\ d\}\\\\C=\{0,\ a,\ 2,\ b\}\\\\B\ \cup\ C=\{a,\ b,\ c,\ d,\ 0,\ 2\}

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Put the quadratic into vertex form and state the coordinates of the vertex. y= y= \,\,x^2-6x-3 x 2 −6x−3
enot [183]

Answer:

y = (x - 3)^2 - 12

(3,-12)

Step-by-step explanation:

Given

y = x^2 - 6x - 3

Solving (a): In vertex form

The vertex form of an equation is:

y = a(x - h)^2 + k

To do this, we make use of completing the square method.

We have:

y = x^2 - 6x - 3

------------------------------------------------------------------

Take the coefficient of x (i.e. -6)

Divide by 2; -6/2 = -3

Square it: (-3)^2 = 9

Add and subtract the result to the equation

------------------------------------------------------------------

y = x^2 - 6x - 3

y = x^2 - 6x + 9 - 9 - 3

y = x^2 - 6x + 9 - 12

Factorize x^2 - 6x + 9

y = x^2 - 3x-3x + 9 - 12

y = x(x - 3)-3(x - 3) - 12

Factor out x - 3

y = (x - 3)(x - 3) - 12

Express as squares

y = (x - 3)^2 - 12

Hence, the vertex form of y = x^2 - 6x - 3 is: y = (x - 3)^2 - 12

Solving (b): State the coordinates of the vertex.

In y = a(x - h)^2 + k; the vertex is: (h,k)

The vertex of y = (x - 3)^2 - 12 will be (3,-12)

3 0
3 years ago
Please you can help me with this problem. Thanks.
Galina-37 [17]

L= 1/8
O=1/4
C=1/8
H=1/8
S=1/8
O or L=3/8
S or C=1/4
S or C or O=1/2
OR mean to add.

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63 is the answer to your problem. Hope this helps!
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