Answer:
Most likely (B)
Step-by-step explanation:
Points of ABCD:
A (3,1)
B (3,4)
C (5,5)
D (5,2)
The algebraic rule for reflecting across the y axis:
(x,y) ---> (-x, y)
Points of ABCD after being reflected: (shown by figure 2)
A (-3, 1)
B (-3, 4)
C (-5, 5)
D (-5, 2)
Then, the figure got translated two units to the left, resulting in figure F in the picture, and A’B’C’D’ in the question.
Points of ABCD after being translated by (x-2, y) : (shown by figure F)
A (-5, 1)
B (-5, 4)
C (-7, 5)
D (-7, 2)
This should be the coordinates of A’B’C’D’.
Given the circumstances, a triangle can be drawn on a circle where the hypothenuse is 5, the leg going right is 4, and the amount going up is 3 (Try visualizing it). Knowing that tangent is opposite over adjacent of theta, tangent would be 3/4
Two ratios that are equivalent to 3:11 are 6:22 and 9:33 :)
Use substitution.
y = 2 - x and y = 4x + 7 can become
2 - x = 4x + 7
Now solve for x
-5 = 5x
-1 = x
Now plug -1 for x in either equation.
y = 2 - x -> y = 2 - (-1) -> y = 3
y = 4x + 7 -> y = 4*-1 + 7 -> y = -4 + 7 -> y = 3
So C) is the correct answer.