The correct answer is 27 i hope this helps
Answer:
The angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees
Given the following angles from the diagram;
m<5 = 55 degrees
m<9 = 80degrees
From the diagram
m<5 = m<1 = 55 degrees (corresponding angle)
m<1 + m<2 = 180 (sum of angle on a straight line)
Hence;
55 + m<2 = 180
m<2 = 180 - 55
m<2 = 125degrees
Also;
m<5 = m<8 = 55 degrees (vertically opposite angle)
m<9 = m<13 = 80degrees
m<13 + m<14 = 180
Hence;
80 + m<14 = 180
m<14 = 180 - 80
m<14 = 100 degrees
Hence the angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees
Step-by-step explanation:
Answer:
x=-3 x=-11
Step-by-step explanation:
−3|x + 7| = −12
|x + 7|=4
x+7=4 x+7=-4
x=-3 x=-11
B is the correct answer,
Here's why!
|x+3|<2
case 1 and case 2 states you need to invert it to see which either is
case 1 would be
|-x-3|<2
-x< 5
x>-5
and on the other case
case 2 would be
x+3<2
x<-1
so this means that
B would be your answer!
x>-5 and x<-1
Please mark brainlyist!
The direction of a vector is the orientation of the vector, that is, the angle it makes with the x-axis.
The magnitude of a vector is its length.
The formulas to find the magnitude and direction of a vector are:
![\begin{gathered} u=❬x,y❭\Rightarrow\text{ Vector} \\ \mleft\Vert u|\mright|=\sqrt[]{x^2+y^2}\Rightarrow\text{ Magnitude} \\ \theta=\tan ^{-1}(\frac{y}{x})\Rightarrow\text{ Direction} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20u%3D%E2%9D%ACx%2Cy%E2%9D%AD%5CRightarrow%5Ctext%7B%20Vector%7D%20%5C%5C%20%5Cmleft%5CVert%20u%7C%5Cmright%7C%3D%5Csqrt%5B%5D%7Bx%5E2%2By%5E2%7D%5CRightarrow%5Ctext%7B%20Magnitude%7D%20%5C%5C%20%5Ctheta%3D%5Ctan%20%5E%7B-1%7D%28%5Cfrac%7By%7D%7Bx%7D%29%5CRightarrow%5Ctext%7B%20Direction%7D%20%5Cend%7Bgathered%7D)
In this case, we have:
• Magnitude
![\begin{gathered} w=❬-10,-12❭ \\ \Vert w||=\sqrt[]{(-10)^2+(-12)^2} \\ \Vert w||=\sqrt[]{100+144} \\ \Vert w||=\sqrt[]{244} \\ \Vert w||\approx15.620\Rightarrow\text{ The symbol }\approx\text{ is read 'approximately'} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20w%3D%E2%9D%AC-10%2C-12%E2%9D%AD%20%5C%5C%20%5CVert%20w%7C%7C%3D%5Csqrt%5B%5D%7B%28-10%29%5E2%2B%28-12%29%5E2%7D%20%5C%5C%20%5CVert%20w%7C%7C%3D%5Csqrt%5B%5D%7B100%2B144%7D%20%5C%5C%20%5CVert%20w%7C%7C%3D%5Csqrt%5B%5D%7B244%7D%20%5C%5C%20%5CVert%20w%7C%7C%5Capprox15.620%5CRightarrow%5Ctext%7B%20The%20symbol%20%7D%5Capprox%5Ctext%7B%20is%20read%20%27approximately%27%7D%20%5Cend%7Bgathered%7D)
• Direction
Therefore, the magnitude and direction of the vector are:
