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zalisa [80]
3 years ago
10

Jo participated in a read-a-thon to raise money for a local library. She raised $20 plus $1.50 per book that she red. She raised

a total of $59. Let X represent the number of books Jo read. In the first blank, write an equation that can be used yo determine the number of books Jo read. In the second blank, answer how many books did she read?

Mathematics
1 answer:
maw [93]3 years ago
3 0

Multiply 1.50 by x ( number of books read and add it to the 20:

Equation: y = 20 + 1.50x

Replace y with the amount she raised and solve for x:

59 = 20 + 1.50x

Subtract 20 from both sides:

39 = 1.50x

Divide both sides by 1.50:

x = 39 /1.50 = 26 books were read.

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Triangle A B C. Angle C is 80 degrees and angles B and A are y degrees. What is the value of y in the triangle? Angle y = °
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You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on con
AlladinOne [14]

Using the z-distribution, a sample size of 180 is needed for the estimate.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 98% confidence level, hence\alpha = 0.98, z is the value of Z that has a p-value of \frac{1+0.98}{2} = 0.99, so the critical value is z = 2.327.

The population standard deviation is of \sigma = 23, and to find the sample size, we have to solve for n when M = 4.

Hence:

M = z\frac{\sigma}{\sqrt{n}}

4 = 2.327\frac{23}{\sqrt{n}}

4\sqrt{n} = 2.327 \times 23

\sqrt{n} = \frac{2.327 \times 23}{4}

(\sqrt{n}) = \left(\frac{2.327 \times 23}{4}\right)^2

n = 179.03.

Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

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