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ipn [44]
3 years ago
8

the price of a video game was reduced from $70 to $55. By what percentage was the price of the video game reduced?

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

21.4% or 21%

Step-by-step explanation:

70 - 55 = $15

(15 / 70) × 100 = %

0.214 × 100 = 21.4%

pychu [463]3 years ago
4 0

Answer: 21.43%

Step-by-step explanation: X/100 * 70 = 55

70X/100 = 55

7X/10 =55

7X = 55 * 10

7X = 550

Divide both sides by 7

7X/7 = 550/7

X = 78.57%

Hence, 100% - 78.57% = 21.43%

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Isaiah is designing a new board game, and is trying to figure out all the possible outcomes. How many different possible outcome
motikmotik

Answer:

  • 48 outcomes

Step-by-step explanation:

<u>Outcomes</u>

  • 6 for the die, 4 for the spinner, 2 for the coin

<u>Total outcomes:</u>

  • 6*4*2 = 48
7 0
3 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard dev
Nesterboy [21]

Answer:

There is a 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard deviation of 2.1-cm. This means that \mu = 201.9, \sigma = 2.1.

For shipment, 9 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

By the Central Limit Theorem, since we are using the mean of the sample, we have to use the standard deviation of the sample in the Z formula. That is:

s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{9}} = 0.7

This probability is 1 subtracted by the pvalue of Z when X = 204.1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{204.1 - 201.9}{0.7}

Z = 3.14

Z = 3.14 has a pvalue of 0.9992. This means that there is a 1-0.9992 = 0.0008 = 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

3 0
3 years ago
Evaluate 11-(-8)-(-3)
VMariaS [17]

Answer:

22

Step-by-step explanation:

11-(-8)-(-3)

19-(3)

19+3

22

hope i helped:)

6 0
3 years ago
Can you help me with question 32? Quadratic Equations
bagirrra123 [75]
Lets x = width
height = 2x - 4

A = 1/2 b h
63 = 1/2 (x)(2x-4)
126 = 2x^2 - 4x
2(x^2 - 2x - 63) = 0
2(x - 9)(x + 7) = 0
x - 9 = 0; x = 9
x + 7 = 0; x = -7

so width = 9
height = 2(9) - 4 = 18 - 4 = 14

answer
width = 9 in
height = 14 in
8 0
4 years ago
Find the value of x. The angle measures of a right triangle are <br>x°<br>8x°​
lianna [129]

Answer:

x equals 10

Step-by-step explanation:

All triangles have 180 degrees

The bottom left angle is a right angle and is therefore 90°

That leaves us with x+8x=90°

9x=90°

x=10°

8 0
3 years ago
Read 2 more answers
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