Then, the median is found by taking the mean (or average) of the two middle most numbers.
A=11.55in²<span><span><span>lLengthin</span><span>wWidthin</span></span></span>
<span>1. 5564÷91
I know that 9 * 6 = 56
5564 rounds to 5600
91 rounds to 9
Since 56/9 = 6, then 5600/90 is the same as 560/9 = 60
The estimate is 60
2. </span><span>5391÷25
5391 sounds to 5400
25 is 1/4 of 100.
That means when you divide by 25, you can divide by 100 and multiply by 4.
5400/100 = 54
54 * 4 = 216
Estimate: 216
3. </span><span>explain how to estimate 498÷12
48/12 = 4
498 is little more than 480, so 498/12 is little more than 40
4. </span><span>which is the closest estimate for 2130÷ 33
A.7 B.17 C.70 D.700
2130/33
Round off the numerator and denominator to
2100/30
Reduce the fraction
210/3
Since I know that 21/3 = 7, then 210/3 = 70
Estimate: 70
</span>
Answer:
There are 200 students in the seventh grade.
Step-by-step explanation:
For equations like these, you have to use the is/of formula, which is:
Percent/100 = is/of.
Since you are trying to find how many students are in the seventh grade, this means that 52 <u><em>is</em></u> 26% of the total amount of students in the seventh grade. So, the formula would look like so:
26/100 = 52/n.
Next, you have to cross multiply, which means you would multiply 26 by n, and 52 by 100.
Then, you are going to have this left over from the cross multiplying:
5200 = 26n.
Divide 26 on both sides, leaving you with:
1n = 200, or n = 200.
54. 30
^ ^
27 2. 10 3
^ ^
9 3. 5 2
^
3 3
They only have 3 and two in common when you fully factor them. 3×2= 6
6 is the greatest common factor.
