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rewona [7]
3 years ago
8

darnel’s retirement party cost $33, plus an additional $1 for each guest he invites. what is the maximum number of guests there

can be if darnel can afford to spend a total of $42 on his retirement party?
Mathematics
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

20

Step-by-step explanation:

He's going to need a very sharp pencil to cross out the people he cannot afford to invite but would like to.

Equation

y = 33 + 1x

y = 42

42 = 33  + x

Solution

42 = 22 + x               Subtract 22 from both sides.

42 - 22 = 22 -22 + x    

20 = x

This means that if each extra person costs $1.00 then he can invite 20 more people (20 * 1 = 20)

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Answer:

-11x+12

Step-by-step explanation:

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8 0
2 years ago
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Can u solve the answer
pickupchik [31]

Answer:

She needs 50 ft² of wood to cover the table

Step-by-step explanation:

You need to know the formula for area of a trapezoid, which is

A = (B1 + B2)h/s     (add the bases together, multiply by the height, then divide

                                by 2)

We are given B1 = 12, B2 = 8, and h = 5, so plug them in and simplify

A = (12 + 8)(5)/2

 

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       A = 100/2

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5 0
3 years ago
A calculator displays a result as 1.3540980 107 kg. the estimated uncertainty in the result is ±2%. how many digits should be i
yan [13]
<span>2 significant digits.
       
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3 0
3 years ago
An item is regularly priced at $33. It is now priced at a discount of 65% off the regular price.
Vinil7 [7]
Step by step explanation:

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3 0
2 years ago
A game of chance involves rolling an unevenly balanced 4-sided die. The probability that a roll comes up 1 is 0.21, the probabil
WITCHER [35]

Answer:

2.65 dollars

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x1P(x1) + x2P(x2) + ... + xnP(xn)

Where x1, x2, ... , xn are the possibles values of the variable and P(x1), P(x2), ... , P(xn) are the probabilities of x1, x2, ... , xn respectively.

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E(x) = $1(0.21) + $2(0.21) + $3(0.3) + $4(0.28)

E(x) = $2.65

4 0
3 years ago
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