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rewona [7]
3 years ago
8

darnel’s retirement party cost $33, plus an additional $1 for each guest he invites. what is the maximum number of guests there

can be if darnel can afford to spend a total of $42 on his retirement party?
Mathematics
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

20

Step-by-step explanation:

He's going to need a very sharp pencil to cross out the people he cannot afford to invite but would like to.

Equation

y = 33 + 1x

y = 42

42 = 33  + x

Solution

42 = 22 + x               Subtract 22 from both sides.

42 - 22 = 22 -22 + x    

20 = x

This means that if each extra person costs $1.00 then he can invite 20 more people (20 * 1 = 20)

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Answer:

Step-by-step explanation:

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Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

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Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...

Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

Time = 11\frac{2}{3}\ min

<em>This implies that they go on round after </em>11\frac{2}{3}\ min<em></em>

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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