Answer:
The rate at which water leaking is
gal/min.
Step-by-step explanation:
Given:
A large container holds 8 gallons of water.
After 56 minutes the container only has 1 gallon of water left.
Now, to find at what rate is the water leaking.
So, water leaked from the container = 8 gallons - 1 gallon = 7 gallons.
Time taken for leakage = 56 minutes.
<em>Now, to get the rate:</em>
![\frac{Gallons\ of\ water\ leaked}{Time\ taken\ for\ leakage}](https://tex.z-dn.net/?f=%5Cfrac%7BGallons%5C%20of%5C%20water%5C%20leaked%7D%7BTime%5C%20taken%5C%20for%5C%20leakage%7D)
![=\frac{7 gallons}{56 minutes}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B7%20gallons%7D%7B56%20minutes%7D)
![=\frac{1 gallon}{8 minutes}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%20gallon%7D%7B8%20minutes%7D)
The rate =
gal/min.
Therefore, the rate at which water is leaking is
gal/min.
Answer:
x = 2.
Step-by-step explanation:
3^2x = 9^(3x - 4)
9^3x-4 = 3^2x
(3^2)^(3x-4) = 3 ^2x
3^6x-8 = 3^2x
6x - 8 = 2x
4x = 8
x = 2 (answer).
Answer:
Simple
Rise/Run
for one week they run 10 miles
2 weeks 20 miles
3 weeks 30 miles
4 weeks 40 miles
the rate of change would be 10/1 (Why? Because you rise +10 each time per week.)
divide that it would be 10 (:
gOoD lUCk
second answer copied me so.