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olga55 [171]
2 years ago
14

Solve for x . Leave your answer in the simplest form

Mathematics
1 answer:
Alisiya [41]2 years ago
3 0

Hello!

Here we are given a composite shape, meaning that we can divide this shape up into ways that we are given formulas to solve for legs and such.

I can see here that this can be divided into a triangle and a rectangle using a horizontal line.

The leg lengths of this triangle would be 9, because it is congruent to the bottom side of the rectangle, and 7, because it is the left side minus the right side.

This would also make a right triangle, meaning we could solve for the hypotenuse utilizing the Pythagorean Theorem.

a^2+b^2=c^2

6^2+7^2=c^2

36+49=c^2

c^2=85

c=\sqrt{85}

Which is in simplest radical form.

Hope this helps!

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3 years ago
in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume
Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The m\angle CAB and m\angle CAD.

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

m(arcADC)=m(arcAD)+m(arcDC)

228^\circ=180^\circ+m(arcDC)

228^\circ-180^\circ+=m(arcDC)

48^\circ+=m(arcDC)

The measure inscribed angle is half of the corresponding subtended arc.

m\angle CAD=\dfrac{1}{2}\times m(arcDC)

m\angle CAD=\dfrac{1}{2}\times 48^\circ

m\angle CAD=24^\circ

AB is the tangent. So, m\angle BAD=90^\circ because radius is perpendicular on the tangent and the point of tangency.

m\angle BAD=m\angle CAB+m\angle CAD

90^\circ=m\angle CAB+24^\circ

90^\circ -24^\circ=m\angle CAB

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Therefore, m\angle CAB=66^\circ and m\angle CAD=24^\circ.

4 0
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