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4 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

aleksandrvk [35]4 years ago

5 0

Answer:

Two

Step-by-step explanation:

The table is saying that, if Sandra swam enough races, she should expect to get 20 firsts, 12 seconds, 6 thirds, and two no placements.

Her expected value of points will be the average (mean) of all the points awarded for each race.

The average is the total number of points divided by the number of races.

$\begin{array}{cccl}\textbf{Points} & & \textbf{Total}\\\textbf{Awarded} & \textbf{Frequency} & \textbf{Points}\\3 & 20 & 60\\2 & 12 & 24\\1 & 6 & 6\\0 & 2 & 0\\\textbf{TOTAL} & \mathbf{40} & \mathbf{90}\\\end{array}$

The simulation says that, if she swam 40 races, she should expect to earn a total of 90 points.

$\text{Average} = \dfrac{\text{Total points}}{\text{Number of races }} = \dfrac{\text{90}}{\text{40}} =\textbf{2.25 points/race}$

She can't win a fraction of a point, so she can expect to win two points in her first race.

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You can model an arch at your school using the equation y=−0.9(x+3)(x−3), where x and y are measured in feet. The x-axis represe

Slav-nsk [51]

Answer:

6 ft

Step-by-step explanation:

As we know that, the arch meet the ground are the value of x when y = 0

y=−0.9(x+3)(x−3)

<=> 0 = −0.9(x+3)(x−3)

<=> x=3 or x=-3

So we have 2 coordinates: (3, 0) and (-3,0) and the distance between them is:

3 -(-3) = 6

=> The width of the arch at ground level is 6 ft

7 0

3 years ago

the mean score for 10 students on the chemistry final exam was 178. however, the teacher has made a mistake and recorded one stu

lawyer [7]

The mean should be 177.

8 0

3 years ago

- If f(x) = x3 - 2, find f(3). O 25 O 24 O 26 O 20

kolezko [41]

Answer:

Option A, $25$

Step-by-step explanation:

Step 1: Plug in 3 for x and solve

$f(x) = x^3 - 2$

$f(3) = (3)^3 - 2$

$f(3) = 27 - 2$

$f(3) = 25$

Answer: Option A, $25$

5 0

2 years ago

Ok i’m stuck on this one

Natali [406]

180-149= 31
180-119-31=30
m<1=30

8 0

3 years ago

Read 2 more answers

A function $f$ has a horizontal asymptote of $y = -4,$ a vertical asymptote of $x = 3,$ and an $x$-intercept at $(1,0).$ Part (a

Masja [62]

1. $f$ has a horizontal asymptote at $y=-4$

This means that

$\displaystyle\lim_{x\to\pm\infty}f(x)-(-4)=0$

(for at least one of these limits)

2. $f$ has a vertical asymptote at $x=3$

This means that $f$ has a non-removable discontinuity at $x=3$ . Since $f$ is some rational function, there must be a factor of $x-3$ in its denominator.

3. $f$ has an $x$ -intercept at (1, 0)

This means $f(1)=0$ .

(a) With

$f(x)=\dfrac{ax+b}{x+c}$

the second point above suggests $c=-3$ . The first point tells us that

$\displaystyle\lim_{x\to\pm\infty}\frac{ax+b}{x-3}+4=0=\lim_{x\to\pm\infty}\frac{ax+b+4x-3}{x-3}=0$

In order for the limit to be 0, the denominator's degree should exceed the numerator's degree; the only way for this to happen is if $a=-4$ so that the linear terms vanish.