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3 years ago

6

A football team loses 4 yards on one play and 7 yards on another play. Write a sum of negative integers to represent this situat

ion. Find the sum and explain how it is related to the problem.

1 answer:

Shtirlitz [24]3 years ago

3 0

Answer:

-11 yards

Step-by-step explanation:

the first loss is represented by -4 and the second loss is represented by -7.

The sum of negative numbers will be:

(-4) + (-7) = -11

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Can you help me with 1 & 3?

iVinArrow [24]

For 1 multiply both sides by 3 which gives you 3y-y=12. Then combine like terms 2y=12. Lastly divide both sides by 2 and you get y=6. And for 3 first multiply both sides by 4 which gives you 6y-32=y+8. After that combine like terms 6y-y-32=8. Now add the equation together 5y=40 and then divide by 5 and get y=8

5 0

4 years ago

The sum of 2 of the exterior angles of a triangle is 222 degrees. What is the measure of the third exterior angle?

zysi [14]

Answer:

Exterior angles always add up to 360 degrees, therfore 360 - 222 = 138

Step-by-step explanation:

360 - 222 = 138

the answer to your question is 138degrees.

For any shape the exterior angles will always add up to 260 degrees.

Hope this helps in the future!

5 0

3 years ago

Read 2 more answers

Given the function f(x)=6x-11, find f(-1/3).

Nadya [2.5K]

Answer:

-13

Step-by-step explanation:

(-1/3)*6 = -2

f(-1/3) = -2 -11

f(-1/3) = -13

7 0

3 years ago

La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

malfutka [58]

Answer:

Falso.

Step-by-step explanation:

Sea $d = \frac{a}{b}$ un número racional, donde $a, b \in \mathbb{R}$ y $b \neq 0$ , su opuesto es un número real $c = -\left(\frac{a}{b} \right)$ . En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) <em>El exponente es cero.</em>

(b) <em>El exponente es un negativo impar.</em>

(c) <em>El exponente es un negativo par.</em>

(d) <em>El exponente es un positivo impar.</em>

(e) <em>El exponente es un positivo par.</em>

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, $c = d = 1$ . La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

$d' = d^{-n}$ y $c' = c^{-n}$

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

$d' = \left(\frac{a}{b} \right)^{-n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}$

$d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}$

$d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}$ y $c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[-\left(\frac{b}{a} \right)\right]^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = - \left(\frac{b}{a} \right)^{n}$

Puesto que $d' \neq c'$ , la proposición es falsa.

(c) El exponente es un negativo par.

Si $n$ es par, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left(\frac{b}{a} \right)^{n}$

Puesto que $d' = c'$ , la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

$d' = d^{n}$ y $c' = c^{n}$

$d' = \left(\frac{a}{b}\right)^{n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = - \left(\frac{a}{b} \right)^{n}$

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left(\frac{a}{b} \right)^{n}$

Si $n$ es par, entonces $d' = c'$ y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

3 0

3 years ago

The corporate office sent out a memo stating that due to productivity increases, all salaried employees would receive 30% more a

Step2247 [10]

Basically, the question is asking, what will happen if we increase 9 by 30%?

first, what is 30% of 9?
$\frac{30}{100}*9= \frac{3*9}{10} =2.7$

So, the increase will be by 2.7 days,

So the total amount will be 9+2.7=11.7 - this is the correct answer.

6 0

3 years ago

Read 2 more answers