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satela [25.4K]
3 years ago
11

There are 36 large fish tanks at the zoo.

Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0

You would multiply the tanks by gallons
36x205
= 7,380
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A small group of students are aged 12, 14, 12, 15, 14, 13, 12, 12. What is their mean age?
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Brainliest for the first correct answer! Which scenario is modeled in the diagram below? (look at attached image)
EleoNora [17]

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D) Kaia saved $165.45 on a new guitar because it was 75 percent off. The price of the guitar before the discount was $220.60.

Step-by-step explanation:

Given in the attached diagram shows a model of a discount given on a purchase of guitar showing 75% of the price of guitar ($55.15 + $55.15 + $55.15) that was given.

It also tells that the price pays is 25% of the price of the guitar before the discount. I.e. 25% of %220.60 = 0.25 × 220.60 = $55.15.

From the diagram given, we can infer that Kaia bought the guitar at $55.15 while saving $165.45. That is 25% of the original price. And the amount saved, $165.45, is %75 of the original price ($55.15+$55.15+$55.15).

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Look at the factors of 18 and 30. What is the greatest common factor? factors of 18: 1, 2, 3, 6, 9, 18 factors of 30: 1, 2, 3, 5
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The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
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