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Zolol [24]
3 years ago
13

5 Stars and Brainliest to correct answer

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0
At θ = 90°, the equation must evaluate to zero. The only one that does that is the 1st choice ...
  r = 2 - 2sin(θ)

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Please help me !!!!!
romanna [79]

Answer:

3/8

Step-by-step explanation:

If 1 and 3 are odd numbers then all you have to do is count the number of 1 and 3's(3). then count the number of numbers (8).

3 0
2 years ago
I need help on this???
Aliun [14]
Use the geometric mean for right triangles here.  Like this \frac{9}{y}= \frac{y}{7}.  Cross multiply to get y^{2}=63, and y= \sqrt{63}.  That simplifies down to y= \sqrt{9*7}.  Pull out the 9 as a perfect square of 3 and you're left with y=3 \sqrt{7}, first choice above.
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3 years ago
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I need help solving $27 ticket with 10% discount
weqwewe [10]

The answer would be $2.70

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3 years ago
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What is the value of y = sin (? when ? = 0°?
Montano1993 [528]
Y=sin(? when ?=0° the answer is 0

Y=0
3 0
3 years ago
The weight for crates of apples is normally distributed with a mean weight of 34.6 pounds and a standard deviation of 2.8 pounds
Tatiana [17]

Answer:

42.22% probability that the weight is between 31 and 35 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 34.6, \sigma = 2.8

What is the probability that the weight is between 31 and 35 pounds

This is the pvalue of Z when X = 35 subtracted by the pvalue of Z when X = 31. So

X = 35

Z = \frac{X - \mu}{\sigma}

Z = \frac{35 - 34.6}{2.8}

Z = 0.14

Z = 0.14 has a pvalue of 0.5557

X = 31

Z = \frac{X - \mu}{\sigma}

Z = \frac{31 - 34.6}{2.8}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

0.5557 - 0.1335 = 0.4222

42.22% probability that the weight is between 31 and 35 pounds

6 0
3 years ago
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