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noname [10]
3 years ago
10

Tan Please help I’m on a time limit

Mathematics
2 answers:
Leto [7]3 years ago
5 0

Answer:

8/15

Step-by-step explanation:

igomit [66]3 years ago
3 0
The answer to the question is 8/15
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Vector A⃗ has magnitude 5.00 and is at an angle of 36.9∘ south of east. Vector B⃗ has magnitude 6.40 and is at an angle of 20.0∘
timama [110]

Answer:

3.9984i-3.0021j

Step-by-step explanation:

Due to the fact that we are only asked for the components on A, we will focus on that information.

The first thing we need to do is to dimension the magnitud of A as a hypotenuse of a right triangle. As the vector is ponting in south-east direction, we can asume that it´s (i) component will be positive and it´s (j) component will be negative.

Now, using trigonometric functions we can find the components of the vector A by multiplying the magnitude by -sin(x) for (j) and cos(x) for (i).

-5sin(36.9)=-3.0021

(this component is negative due to the fact that the vector is pointing down)

5cos(36.9)= 3.9984

Now we write in the correct notation x(i) + y(j)

3.9984i-3.0021j

8 0
4 years ago
A cone has a radius of 3 m and a height of 10 m find the volume of the cone. Round your answer to the nearest 10th if necessary.
Artemon [7]
V of a cone= 1/2*pi * r^{2} *h
V=1/2*pi*r^2*h = .5*pi*(9)*(10) = 141.4m^3
5 0
4 years ago
Select the correct answer.
8_murik_8 [283]

Answer:

B

Step-by-step explanation:

This is because it is the lowest point on the line.

3 0
3 years ago
A)distributive property of multiplication over subtraction
alina1380 [7]

Answer: sup brendalys it’s me Timotheus

Step-by-step explanation:

The answer is c I think

5 0
3 years ago
Solve the equation 2x^2 + 16x + 21 = 0 to the nearest tenth.
Crank

Answer:

Rounded to the nearest tenth the solutions to the equation are:

x = -1.7   and x = -6.3

Step-by-step explanation:

Since this is a quadratic equation of the form:

ax^2+bx+c=0

Use the quadratic formula, which tells you that the solutions would be given by:

x=\frac{-b+-\sqrt{b^2-4ac} }{2a}

So in our case, the quadratic formula gives:

x=\frac{-b+-\sqrt{b^2-4ac} }{2a}\\x=\frac{-16+-\sqrt{16^2-4(2)(21)} }{2*2}\\x=\frac{-16+-\sqrt{88} }{4}

which gives us two real solutions:

x = - 1.654792

x = -6.345207

Which rounded to the nearest tenth give:

x = -1.7   and x = -6.3

3 0
3 years ago
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