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Roman55 [17]
4 years ago
5

Paul's family drove 377 mi to the beach averaging 58 ​ mi/h ​ on the way there. On the return trip home, they averaged 65 ​ mi/h

​ .
What was the total time Paul's family spent driving to and from the beach?

11.3 h

11.6 h

12.3 h

13 h
Mathematics
1 answer:
Jet001 [13]4 years ago
6 0

The answer is 12.3 hours.

On the way to the beach, the family averaged 58 mi/h over 377 mi, so we take 377/58 to find the amount of time spent going to the beach. 377/58 = 6.5 hours.

On the way back, they averaged 65 mi/h over the same 377 mi, so we take 377/65. 377/65 = 5.8 hours.

6.5 + 5.8 = 12.3


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Answer:

<h2>x+5y+z = 25</h2>

Step-by-step explanation:

Given a plane passing through the point(1, 5,-1) and perpendicular to the vector (1, 5, 1), the equation of the plane can be expressed generally as;

a(x-x₀)+b(y-y₀)+c(z-z₀) = 0 where (x₀, y₀, z₀) is the point on the plane and (a, b,c) is the normal vector perpendicular to the plane i.e (1,5,1)

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Substituting this point in the formula we will have;

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1(x-1)+5(y-5)+1(z-(-1)) = 0

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<u>ANSWER:</u>

The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)

<u>SOLUTION: </u>

Given, the midpoint of AB is M(-5,1).  

The coordinates of A are (-4,-5),  

We need to find the coordinates of B.

We know that, mid-point formula for two points A(x_{1}, y_{1}) and B (x_{1}, y_{2}) is given by

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