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likoan [24]
4 years ago
14

What is the septum and where is it located

Mathematics
1 answer:
Neporo4naja [7]4 years ago
5 0
Is a wall, dividing a cavity or structure into smaller ones

The nasal septum separates the left and right airways in the nose, dividing the two nostrils.

It is depressed by the depressor septi nasi muscle.

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I need help with this question. i keep having trouble
nignag [31]

Answer:

Step-by-step explanation:

The angles <JKL, <EKL, and <JKE form a full angle which means their sum is equal to 360:

134 + 21x + 6 + 5x = 360 add like terms

140 + 26x = 360 subtract 140 from both sides

26x = 220 divide both sides by 26

x = 8.4 approximately

to find the angle m<JKL replace x with the value we found.

8 0
3 years ago
Can someone give me a answer key for Vocabulary Test Course 1 Chapter 4 Multiply and Divide Fractions​
serg [7]

Answer:https://quiz.let.com/216018638/course-1-chapter-4-multiply-divide-fractions-6ns1-6rp3-3d-flash-cards/

remove the period between quiz and let but there is a quizlet on it

Step-by-step explanation:

5 0
3 years ago
12 times 2278 divided by 34 take away 35
anygoal [31]

Answer:

9,613

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please explain to me how to find y. I’m so confused.
koban [17]
Every triangle angles add up to 180.

So because one angle is 90 degrees you would subtract it from 180 to get 90 and then divide it by two which is 45 degrees.

Hope this helps, have a nice day! :)
7 0
3 years ago
Two collinear points on a line are given in the table below:
katrin [286]

Answer:

(4,3) and (7,2) do not lie on the line

Step-by-step explanation:

Given

(0,0)\ and\ (2,1)

Required

Determine which points that are not on the line

First, we need to determine the slope (m) of the line:

m = \frac{y_2 - y_1}{x_2- x_1}

Where

(x_1,y_1) = (0,0)

(x_2,y_2) = (2,1)

So;

m = \frac{y_2 - y_1}{x_2- x_1}

m = \frac{1 - 0}{2-0}

m = \frac{1}{2}

Next, we determine the line equation using:

y - y_1 = m(x -x_1)

Where

m = \frac{1}{2}

(x_1,y_1) = (0,0)

y - y_1 = m(x -x_1) becomes

y - 0 = \frac{1}{2}(x - 0)

y = \frac{1}{2}x

To determine which point is on the line, we simply plug in the  values of x to in the equation check.

For (4,2)

x = 4 and y =2

Substitute 4 for x and 2 for y in y = \frac{1}{2}x

2 = \frac{1}{2} * 4

2 = \frac{4}{2}

2=2

<em>This point is on the graph</em>

<em></em>

For (4,3)

x = 4 and y = 3

Substitute 4 for x and 3 for y in y = \frac{1}{2}x

3 = \frac{1}{2} * 4

3 = \frac{4}{2}

3 \neq 2

<em>This point is not on the graph</em>

<em></em>

For (7,2)

x = 7 and y = 2

Substitute 7 for x and 2 for y in y = \frac{1}{2}x

2 = \frac{1}{2} * 7

2 = \frac{7}{2}

2 \neq 3.5

<em></em>

<em>This point is not on the graph</em>

<em></em>

<em></em>(\frac{4}{8},\frac{2}{8})<em></em>

<em></em>x = \frac{4}{8} and<em> </em>y = \frac{2}{8}<em></em>

<em>Substitute </em>\frac{4}{8}<em> for x and </em>\frac{2}{8}<em> for y in </em>y = \frac{1}{2}x<em></em>

<em></em>\frac{2}{8} = \frac{1}{2} * \frac{4}{8}<em></em>

<em></em>\frac{2}{8} = \frac{1 * 4}{8 * 2}<em></em>

<em></em>\frac{2}{8} = \frac{4}{16}<em></em>

<em></em>\frac{1}{4} = \frac{1}{4}<em></em>

<em></em>

<em>This point is on the graph</em>

3 0
3 years ago
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