Mushrooms and other things.. sorry I know this isn't the best answer but I hope it helps
The subatomic particle you are looking for is the answer of an electron Force you're 100% right
Answer:
A. 21 rad/s
B. 200.5 rpm
C. 26.46 rad/s2
D. 0.299 Hz
Explanation:
Parameters given are:
Tangential velocity,v = 1.26m/s
Diameter (outer edge) = 0.120m
Outer edge radius, ro = 0.12/2
= 0.06m
A. Calculate Angular velocity
Angular velocity, w = v/r
= v/ro
= 1.26/0.06 = 21 rad/s
In rpm,
2pi/60 rad/s = 1 rpm
1 rad/s = 60/2pi rpm
Sp, 21 rad/s = 60 * 21/2pi rpm
= 200.5 rpm
B. Calculate the inner edge radius, ri given w = 500 rpm
Converting rpm to rad/s,
= 2pi/60 * 500 rad/s
= 52.34 rad/s
ri = v/w
= 1.26/ 52.36
= 0.024m
C. Calculating centripetal acceleration, a from the outer edge, ro
a = v2/r = w2r
= (1.26)2/0.06
= 26.46 rad/s
D. Calculate the frequency, f of the outer edge angular velocity, w = 21 rad/s
f = 2pi/w
= 2pi/21
= 0.299 Hz (or per second)
If this is a true or false, question I will help you by saying that this statement is FALSE.
Answer:
The answer is: B) Twice the true concentration
Explanation:
According to what was expressed in the problem, the experiment has to be done with 200 ul of solution, with 200 ul of DNS and finally with 400 ul of H2O. The expression in the problem says that 100 ul of solution is recovered and 100 ul of DNS are added, and 200 ul of H2O are added, but it is said that only half of the solution was added (100 ul of H2O), leading to a increase in glucose concentration.
