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grin007 [14]
3 years ago
12

1. Tell whether the number 47 is prime

Mathematics
2 answers:
kenny6666 [7]3 years ago
8 0

Answer:47 is a prime and 81 is a composite

Step-by-step explanation:47={1,47}

81={1,3,9,18,27,81}

Rina8888 [55]3 years ago
8 0

1. The number 47 is prime. The only factors are 1 and itself. We can check by dividing 47 over the list of primes smaller than 47. To be more efficient, we can stop once we reach sqrt(47) = 6.85. So we only need to check the primes {2, 3, 5} to show they are not factors of 47 to show that 47 is prime.

=====================================

2. The number 81 is composite. It is not prime because it has factors other than 1 and itself.

There are 5 factors and they are

1, 3, 9, 27, 81

Note how each factor listed is a power of 3 (1 = 3^0, 3 = 3^1, 9 = 3^2, 27 = 3^3, 81 = 3^4)

The prime factorization of 81 is

81 = 3*3*3*3 = 3^4

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Step-by-step explanation:

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asambeis [7]

Answer:

P(t)=\frac{5}{2} \cdot (\sqrt{2})^t

Step-by-step explanation:

P(2)=5 meants when t=2, that the value for P(t) is 5.

So this gives us this equation:

5=P_0 \cdot a^2

P(4)=10 meants when t=4, that the value for P(t) is 10.

So this gives us this equation:

10=P_0 \cdot a^4

So I take equation 2 and divide it be equation 1 I get:

\frac{10}{5}=\frac{P_0 \cdot a_4}{P_0 \cdot a_2}

Simplifying:

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So plugging into one of my equations I began with gives me an equation to solve for the initial value,P_0:

5=P_0 \cdot (\sqrt{2})^2

5=P_0 \cdot 2

Divide both sides by 2:

\frac{5}{2}=P_0

The function is:

P(t)=\frac{5}{2} \cdot (\sqrt{2})^t

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Step-by-step explanation:

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