<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Answer:
711
Step-by-step explanation:
They used 79/100 of their money on equipment which means if they have a budget of 900 dollars they used...
900*79/100=9*79=711 dollars on equipment.
Answer:
8 sq.units
Step-by-step explanation:
x= base of triangle= 8units
h= height of triangle= 2 units
area of triangle= 1/2*b*h
=1/2* 8* 2
=8 sq.units
<em>Mark me as brainliest please</em>
:Jason is tossing a fair coin. He tosses the coin ten times and it lands on heads eight times. If Jason tosses the coin an eleventh time, what is the probability that it will land on heads?
Solution:
The probability would be ½. The result of the eleventh toss does not depend on the previous
results.
