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faltersainse [42]
2 years ago
5

Help.....................

Mathematics
2 answers:
Yuliya22 [10]2 years ago
7 0

Answer:

See below

Step-by-step explanation:

(0,16) - y axis

(2, -12) - IV

(-1, 2) - II

(3, 0) - x axis

(36.7, 3.9) quadrant I

(-5/8, -5 1/3) - III

alekssr [168]2 years ago
6 0

Answer:

(0,16) Y-axis

(2,-12) Quadrant 4

(-1,2) Quadrant 2

(3,0) X-Axis

(36.7, 3.9) Quadrant 1

(-5/8, -5 1/3) Quadrant 3

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All you need is in the photo ​<br><br><br>please explain step by step
V125BC [204]

Answer:

Hi there

The formula is

A=p (1+r)^t

A future value

P present value

R interest rate

T time

A) A=2,000×(1+0.04)^(3)=2,249.728

B) A=2,000×(1+0.04)^(18)=4,051.63

C) 2500=2000 (1+0.04)^t

Solve for t

T=log(2,500÷2,000)÷log(1+0.04)

T=5.7 years

D) t=log(3,000÷2,000)÷log(1+0.04)

t=10.3 years

Hope it helps

Step-by-step explanation:

7 0
3 years ago
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Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

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3 years ago
In their yard, Larry’s parents decided to plant tomatoes in a certain area. They chose an area that was of a yard long and of a
Marianna [84]

the answer is 18/18 which is the first one

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2 years ago
I need help with sum of my algebra hw assignments
Natalka [10]

Answer:

B

Step-by-step explanation:

Those lines both make up the tip of the triangle figure...  

7 0
2 years ago
1. Delia purchased a new car for $23,350. This make and model straight line depreciates to zero after 13 years.
frosja888 [35]

Answer:

a. y-intercept = 23350 and x-intercept = 13

b. m = -\frac{23350}{13}

c. y = -\frac{23350}{13}x + 23350

Step-by-step explanation:

Given

Years = 13

Total\ depreciation = \$23350

Solving (a): The x and y intercepts

The y intercept is the initial depreciation value

i.e. when x = 0

This value is the value of the car when it was initially purchased.

Hence, the y-intercept = 23350

The x intercept is the year it takes to finish depreciating

i.e. when y = 0

From the question, we understand that it takes 13 years for the car to totally get depreciated.

Hence, the x-intercept = 13

Solving (b): The slope

The slope (m) is the rate of depreciation per year

This is calculated by dividing the total depreciation by the duration.

So:

m = \frac{23350}{13}

Because it is depreciation, it means the slope represents a deduction.

So,

m = -\frac{23350}{13}

Solving (c): The straight line equation

The general format of an equation is:

y = mx + b

Where

m = slope

b = y\ intercept

In (a), we have that:

y\ intercept = 23350

In (b), we have that:

Slope\ (m) = -\frac{23350}{13}

Substitute these values in y = mx + b

y = -\frac{23350}{13}x + 23350

<em>Hence, the depreciation equation is: </em>y = -\frac{23350}{13}x + 23350<em></em>

8 0
3 years ago
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