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Sauron [17]
3 years ago
15

Need help ASAP :) the question is in the picture

Mathematics
1 answer:
nevsk [136]3 years ago
5 0
55- 2v. Or also 55- (2xV)
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I givee brainlilstttt
Alinara [238K]

Answer:

2,1

Step-by-step explanation:

brainliest pls (only if correct)

4 0
3 years ago
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What is the unit rate in dollars for each company?
avanturin [10]
For On call = 10/3.5 = $2.85 for per hour

For talk time 1.25/1/2= $2.5 for per hour
8 0
4 years ago
7. CHALLENGE: Use the digits 0 to 9 to make the equation true. You don't need to use all thedigits you can only use each digit o
labwork [276]

9514 1404 393

Answer:

  20 = 2 + (7 -4) × 6

Step-by-step explanation:

The Order of Operations requires the parentheses be evaluated first, then the multiplication performed. Finally, the addition is performed.

If each of the blanks is filled with a single digit, the result of the multiplication must be a composite number greater than 10. Those are 12, 14, 15, 16, 18, 20. For the expression shown above, we have chosen to make the product be 18. That means the first blank is filled with 2 and the remaining blanks must evaluate to one of the products 2×9 or 3×6.

We have chosen 6 for the last blank, so the two blanks in parentheses must have a difference of 3. The digits 2 and 6 cannot be used, leaving possible choices as (3-0), (4-1), (7-4), (8-5).

Our final expression is chosen to be ...

  20 = 2 +(7 -4)×6

3 0
3 years ago
The owner of a new pet store wishes to display tropical fish in display tanks. The above table shows the species that cannot liv
Pepsi [2]

Answer:

The minimum number of different tanks needed to safely house all the fish is:

  • <u>3 tanks</u>.

Step-by-step explanation:

To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:

  • Tank 1: <em>A</em>
  • Tank 2: <em>F</em>
  • Tank 3: <em>G</em>

Now the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:

  • Tank 1: <em>A, B, D</em>.
  • Tank 2: <em>F, E, H</em>.
  • Tank 3: <em>G, C</em>.

And t<u>he owner of the pet store must buy three different tanks to display these tropical fish</u>.

5 0
3 years ago
PLEASE HELP MEEEEE!!!!!!!
OverLord2011 [107]

Answer:

  1. Cheese: 4\frac{3}{8}  
  2. Milk: 1\frac{2}{3}  
  3. Pasta: 6\frac{1}{4}

Step-by-step explanation:

Cheese:

  1. 1\frac{3}{4} = \frac{7}{4}  
  2. Set up a proportion: \frac{\frac{7}{4} }{4} = \frac{x}{10}  
  3. Cross multiply, then divide: 10 × 7/4 = 17.5, 17.5 ÷ 4 = 4.375
  4. 4.375 = 4\frac{3}{8}  

Milk:

  1. Set up a proportion: \frac{\frac{2}{3} }{4} = \frac{x}{10}  
  2. Cross multiply, then divide: 10 × 2/3 = 6\frac{2}{3}, 6\frac{2}{3} ÷ 4 = 1\frac{2}{3}  

Pasta:

  1. 2\frac{1}{2} = \frac{5}{2}  
  2. Set up a proportion: \frac{\frac{5}{2} }{4} = \frac{x}{10}  
  3. Cross multiply, then divide: 10 × 5/2 = 25, 25 ÷ 4 = 6.25
  4. 6.25 = 6\frac{1}{4}  

I hope this helps!

4 0
3 years ago
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