Answer:
Step-by-step explanation:
Prove: That the sum of the squares of 4 consecutive integers is an even integer.
An integer is a any directed number that has no decimal part or indivisible fractional part. Examples are: 4, 100, 0, -20,-100 etc.
Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;
= 25
= 36
= 49
= 64
The sum of the squares = 25 + 36 + 49 + 64
= 174
Also,
Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;
= 100
= 121
= 144
= 169
The sum of the squares = 100 + 121 + 144 + 169
= 534
Therefore, the sum of the squares of 4 consecutive integers is an even integer.
Answer:
You Can Scan This In The App And Then Its Solved
The Answer Will Be 1.1205 x 10 To The 5th Power.
Solution
g(x) = 2
- 11x
Plugging in x = -1 in g(x), we get
g(-1) = 2
- 11(-1)
Now we have to simplify it.
g(-1) = 2*1 + 11
g(-1) = 2 + 11
g(-1) = 13
So the answer is D) 13.
Thank you. :)