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lorasvet [3.4K]
3 years ago
10

Please help. Me homework is due tomorrow please put them in order

Mathematics
1 answer:
Rufina [12.5K]3 years ago
6 0
4)
y
40
16
4
24
36

5) 4 5/12

9) <


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In a particular class of 27 students,17 are men.what fraction of the student in the class are men
Evgen [1.6K]
p \% \ of \ 27=17 \\\\ \frac{p}{100}*27=17 \\\\ \frac{p}{100}=\frac{17}{27} \\\\ p=\frac{100*17}{27} \\\\ \boxed{p=\frac{1700}{27}}
8 0
3 years ago
Read 2 more answers
Find an explicit formula for the arithmetic sequence -11, -3, 5, 13, ....
Alekssandra [29.7K]

Answer:

<u>b(n) = -11 + (n-1)*8</u>

<u></u>

Step-by-step explanation:

Let n be the sequence number, with n=1 the first number b(1) -11

The sequence changes by +8 each step.

<u><em>b(1)</em></u><em>   -11</em>         + 8 =   -3

<u><em>b(2)</em></u><em>   -3</em>          + 8 =    5

<u><em>b(3)</em></u>   <em> 5 </em>         + 8 =   13

<u><em>b(4)</em></u><em> </em> <em>13</em>

b(1) = -11

b(2) = -3.   or b(1) + 1*8

b(3) =  5,    or b(1) + 2*8

b(4) =  13,   or b(1) + 3*8

We note that each step adds a multiple of 8 to the initial value of -11.  This can be stated as (n-1)*8

The formula for this sequence would be b(n) = b(1) + (n-1)*8

<u>b(n) = -11 + (n-1)*8</u>

Check:  Does n=3 return the value of 5?

b(n) = -11 + (n-1)*8

b(3) = -11 + ((3)-1)*8

b(3) = -11 + (2)*8

b(3) = -11 + 16

b(3) = 5   <u><em>YES</em></u>

5 0
2 years ago
Solve the equation. u+3=7
iogann1982 [59]

Answer: 4

Step-by-step explanation:

u+3=7

u=7-3

u=4

3 0
3 years ago
Please help. I will give five stars and 10 points for correct answer with explanation.
anygoal [31]

Answer:

A: It has no solution

Step-by-step explanation:

1. 3/4z - 1/4z + 3 = 2/4z + 5

2. 2/4z +3 = 2/4z + 5

3. 3 = 5 (No solution because 3 can never be equal to 5)

7 0
3 years ago
Help find the value of x pls I’ll give brainleist.
fenix001 [56]

Answer:

x=2°

Step-by-step explanation:

The given angles are corresponding angles.

Corresponding angles are congruent.

7x+9=9x+5

4=2x

x=2

8 0
3 years ago
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