Answer:
C
Step-by-step explanation:
Solve for each choice until you get the answer 1/5.
A.
2 - 4/5
10/5 - 4/5 = 6/5; this is not 1/5
B
8 - 8/5
40/5 - 8/5 = 32/5; this is not 1/5
C
3 - 16/5
15/5 - 16/5 = -1/5
5 - 26/5
25/5 - 26/5 = -1/5
7 - 36/5
35/5 - 36/5 = -1/5; although this is negative, it still has the same proportionality of 1/5
It looks like you're asked to find the value of y(-1) given its implicit derivative,

and with initial condition y(2) = -1.
The differential equation is separable:

Integrate both sides:


Solve for y :



![y = -\dfrac1{\sqrt[3]{3x+C}}](https://tex.z-dn.net/?f=y%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x%2BC%7D%7D)
Use the initial condition to solve for C :
![y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5](https://tex.z-dn.net/?f=y%282%29%20%3D%20-1%20%5Cimplies%20-1%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes2%2BC%7D%7D%20%5Cimplies%20C%20%3D%20-5)
Then the particular solution to the differential equation is
![y(x) = -\dfrac1{\sqrt[3]{3x-5}}](https://tex.z-dn.net/?f=y%28x%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x-5%7D%7D)
and so
![y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}](https://tex.z-dn.net/?f=y%28-1%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes%28-1%29-5%7D%7D%20%3D%20%5Cboxed%7B%5Cdfrac12%7D)
What it is basically asking is if Y = -4, find the value of x in the equation 6x + 7y = 4x + 4y
To solve this you just need to plug in -4 for y and solve for x
6x + 7(-4) = 4x + 4(-4)
6x - 28 = 4x - 16
Now isolate x by adding 28 to both sides
6x - 28 + 28 = 4x - 16 + 28
6x = 4x + 8
and subtract 4x from both sides
6x - 4x = 4x - 4x + 8
2x = 8
divide both sides by 2
2/2x = 8/2
x = 4
x = 4, y = -2
Answer: (4, - 2)
Hope it helps :)
Bransliest would be appreciated
Answer:
8:9 = eight to nine
Step-by-step explanation:
16:18 - divide each by 2 in order to simplify
= 8:9
-9+x=38
+9. +9
x=47 dats all