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3 years ago

A change in matter that produces one or more new substances is a ???

Chemistry

2 answers:

Dvinal [7]3 years ago

8 0

Chemical reaction, generally speaking. It's a vague definition, but it's easy to remember.

Sliva [168]3 years ago

8 0

The answer is Chemical change or a Chemical reaction. I hope I helped in any way. :)

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5. What are the relative rates of diffusion for methane, CH, and oxygen, O2? If O2 la travels 1.00 m in a certain amount of time

11Alexandr11 [23.1K]

Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of methane gas, m = 16 g/mol

Molar mass of oxygen gas,m' = 32 g/mol

By taking their ratio, we get:

$\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{m'}{m}}$

$\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{32}{16}}=1.4142$

The relative rates of diffusion for methane and oxygen is 1.4142.

If oxygen gas travels 1 meters in time t.

Rate of diffusion of oxygen = $d_{O_2}=\frac{1 m}{t}$

If methane gas travels travels in y meters in time t.

Rate of diffusion of methane= $d_{CH_4}=\frac{y }{t}$

$\frac{d_{CH_4}}{d_{O_2}}=\frac{\frac{y }{t}}{\frac{1 m}{t}}=1.4142$

y = 1.4142 m

Methane gas will be able to travel 1.4142 meter in the same conditions.

8 0

3 years ago

A 5.0 L sample of gas is collected at 400. mmHg at 727 C. What is the volume if the temperature were cooled to 77 C and the pres

saul85 [17]

Answer:

u will equate and make V2 the subject because it's the one u are looking for ....

5 0

3 years ago

Coefficients of the correct balanced equation for the reaction, CaCl2 + AgNO3 ⟶ AgCl + Ca(NO3)2.

mote1985 [20]

Answer:

CaCl2 + 2 AgNO3 ---> 2 AgCl + Ca(NO3)2

6 0

3 years ago

What is the density of a book with a mass of 60g and a volume of 20 cm3?

Vaselesa [24]

Answer:

2.5 g/cm3 .

Explanation:

Density is mass in grams over volume in cubic centimeters. So it is 25 g 10 cm 3 =2.5 g/cm 3 The unit is grams per cubic centimeter. NB - density can also be kilograms over cubic meters Hope this helps!

6 0

3 years ago

What is the mass of 3.75 moles of NaCI? ( Na= 22.99g/mol, CI= 35.45 g/mol)

seraphim [82]

Answer:

219.15 grams

Explanation:

What is the mass of 3.75 moles of NaCI? ( Na= 22.99g/mol, CI= 35.45 g/mol)

Mole of Na = 22.99g

Mole of Cl = 35.45g

For NaCl we have ratio of 1:1, so we have 1 Na for every Cl

So we just add the two together to get the molar mass of NaCl which is

22.99 + 35.45 = 58.44g/mol

And we know we have 3.75 moles of NaCl so we multiply that by the molar mass of NaCl to get our answer

3.75 x 58.44 = 219.15grams

6 0

3 years ago