The pressure is 902 x10 as it has partial adequates which is linguistic in an average point
Answer:
they must have same atomic number and different atomic mass
Answer: Option (C) is the correct answer.
Explanation:
Horticulture is the study of science related to the art of growing fruits, vegetables, or plants.
Therefore, when a person graduated from a college with a degree in horticulture then it means he has obtained enough knowledge about how to grow plants, fruits or vegetables in the best way possible.
Thus, Vincent who also graduated in horticulture cannot accurately tell about human psychology.
Hence, we can conclude that the statement this claim may not be accurate because the blog is produced by someone who is not an expert in the field of human psychology.
By use IUPAC nomenclature rule compound N2O3 is named as
Dinitrogen trioxide ( answer d)
Nitrogen (N2) is named before oxygen(O3) since they are arranged alphabetically. In addition the prefix Di is used infront of nitrogen since they are two nitrogen atoms while prefix tri is used infront of oxide since they are 3 oxygen atoms
Answer:
11.31g NaClO₂
Explanation:
<em> Is given 250mL of a 1.60M chlorous acid HClO2 solution. Ka is 1.110x10⁻². What mass of NaClO₂ should the student dissolve in the HClO2 solution to turn it into a buffer with pH =1.45? </em>
It is possible to answer this question using Henderson-Hasselbalch equation:
pH = pKa + log₁₀ [A⁻] / [HA]
<em>Where pKa is -log Ka = 1.9547; [A⁻] is the concentration of the conjugate base (NaClO₂), [HA] the concentration of the weak acid</em>
You can change the concentration of the substance if you write the moles of the substances:
[Moles HClO₂] = 250mL = 0.25L×(1.60mol /L) = <em>0.40 moles HClO₂</em>
Replacing in H-H expression, as the pH you want is 1.45:
1.45 = 1.9547 + log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]
-0.5047 = log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]
<em>0.3128 = </em>[Moles NaClO₂] / [0.40 moles HClO₂]
0.1251 = Moles NaClO₂
As molar mass of NaClO₂ is 90.44g/mol, mass of 0.1251 moles of NaClO₂ is:
0.1251 moles NaClO₂ ₓ (90.44g / mol) =
<h3>11.31g NaClO₂</h3>
