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scoundrel [369]
4 years ago
12

How do you express 0.00026 in scientific notation

Chemistry
2 answers:
Rus_ich [418]4 years ago
6 0
2.6x10negative4power 2.6x10^-4
Gnesinka [82]4 years ago
4 0
(((2.6 x 10 ^ -4))) yep
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A compound that conducts an electric current in aqueous solution or in the molten state.
makvit [3.9K]

Answer:

  • <em>A compound that conducts an electric current in aqueous solution or in the molten state is</em> a <u>ionic compound</u>.

  • E.g. NaCl (table salt)

Explanation:

Some examples of ionic compounds are NaCl, KF, KI, MgSO₄.

Ionic compounds are formed by positivie ions (named cations) and negative ions (named anions). The strong electrostatic atraction between cations and anions permits the formation of crystals, which are stuctures characterized by a regular pattern. In solid state the ions are in fixed positions.

In order to conduct electricity, the charged particles (cations and anions in the case of the ionic compounds) need to  move freely.

Hence, since in solid state,  ionic compounds do not conduct electric current. But, <em>in molten (liquid) state or in aqueous solution, ionic compounds conduct electric current because, then, the ions move freely.</em>

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3 years ago
Can someone tell me how do I finish this problem?!
Natalija [7]
You can cross multiply, it will be easy
7 0
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The image shows a projection map.
meriva
A. Flat model, Mercator projection
4 0
3 years ago
How many molecules are in 1.95 moles of water?
OLEGan [10]
Water has a molar mass of 18.015 g/mol . This means that one mole of water molecules has a mass of 18.015 g . So, to sum this up, 6.022⋅1023 molecules<span> of water will amount to 1 mole of water, which in turn will have a mass of 18.015 g . 2.7144moles H2O ⋅</span>6.022<span>⋅1023molec.1mole H2O =1.635⋅1024molec.</span>
3 0
3 years ago
Read 2 more answers
Calculate the molar solubility of copper(II) arsenate (Cu3(AsO4)2) in water. Use 7.6 x 10^-36 as the solubility product constant
Molodets [167]
Molar solubility<span> is the number of moles of a substance (the solute) that can be dissolved per liter of solution before the solution becomes saturated. We calculate as follows:

</span>3Cu2+ + 2(AsO4)3-<span> = Cu3(AsO4)2
</span>
7.6 x 10^-36 = (3x^3)(2x^2)
x = 6.62 x 10^-8 M
8 0
3 years ago
Read 2 more answers
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