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scoundrel [369]
3 years ago
12

How do you express 0.00026 in scientific notation

Chemistry
2 answers:
Rus_ich [418]3 years ago
6 0
2.6x10negative4power 2.6x10^-4
Gnesinka [82]3 years ago
4 0
(((2.6 x 10 ^ -4))) yep
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when 6.25 grams of pure iron are allowed to react with oxygen , a black oxide forms. if the product weighs 8.15 g, what is the e
erik [133]
We are given with the mass of  pure iron that reacts with oxygen to form an oxide which has a given mass as well. the mass of oxygen reacted is 8.15-6.25 g or 1.9 grams. THen we convert the mass of the reactants to moles. Iron is equal to 0.1119 moles and oxygen is equal to 0.1188. We divide each number to the less amount. Hence iron is 1 and oxygen is approx 1. The empirical formula hence is FeO or ferrous oxide or Iron (II) oxide.
5 0
3 years ago
When neurotransmitter is released into the synaptic cleft, it is taken up by the post-synaptic neuron.
gogolik [260]

Answer:

<u>Plz make me brainliest</u>

Explanation:

The neurotransmitters released into the cleft diffuse through it to reach the post-synaptic neuron. Neurotransmitters remain in cleft for only some time. They are either taken up by the presynaptic neuron or are broken down by the enzymes present in the synaptic cleft. The post-synaptic neuron contains several receptors on its plasma membrane

7 0
4 years ago
The paths in which electrons travel are called what ovals ,paths,circles,orbitals
PolarNik [594]
The paths in which electrons travel are called orbitals.

8 0
3 years ago
Read 2 more answers
An atom (not a hydrogen atom) absorbs a photon whose associated wavelength is 300 nm and then immediately emits photon whose ass
KIM [24]

Answer:

The net energy is 2.196 eV

Explanation:

Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.

Using:

ΔE = h*c*(1/λ_{1} - 1/λ_{2})

where:

ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602*10^{-19} J.

h = 4.135*10^{-15} eVs

c = 3*10^{8} m/s

λ_{1} = 300 nm = 300*10^{-9} m

λ_{2} = 640 nm = 640*10^{-9} m

Thus:

ΔE = 4.135*10^{-15} eVs*3*10^{8} m/s*(\frac{1}{300*10^{-9}m } }-\frac{1}{640*10^{-9}m })

ΔE = 4.135*10^{-15}*3*10^{8}*1.77*10^{6} eV = 2.196 eV

6 0
3 years ago
If a 185-lb patient is prescribed 145mg. What dosage is the patient receiving in mg/kg of his body weight?
Anestetic [448]

Answer:

1.728 mg/kg

Explanation:

First have to convert the patient's weight to kg

1 lb = 0.454 kg

185 lb in kg = 83.9 kg

Then we have to divide the dose per the weight of the patient

145 mg for 83.9 kg =  145/83.9

= 1.728 mg/kg

7 0
3 years ago
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