Answer PLZZ 50 pointsssss

Mathematics

1 answer:

Yanka [14]3 years ago

6 0

Answers
1.) would be A.) y = 2x + 3
2.) would be graph B) the graph looks a little blurry so it could also be C) just a heads up but I’m almost positive it’s B

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PLEASE HELP IMMEDIATELY! HURRY!

Fynjy0 [20]

Answer:

5 * 5 * 5 * 5

Step-by-step explanation:

Use the rules of Indices.

5⁶⁻²

= 5⁴

8 0

3 years ago

Read 2 more answers

Help pls you get 27 points

Trava [24]

Answer:

C. [-5] < [-3] || D. [-4] < [-2]

Step-by-step explanation:

in A. 5 should be greater, > than -3

in B. 2 should be greater, > than -4

in C. its correct answer. true statement.

in D. its correct answer. true statement.

5 0

2 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$