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zubka84 [21]
3 years ago
12

Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

-1, 1

13, 15

Step-by-step explanation:

x and x+2 are the integers

  • x*(x+2)= 7(x+x+2) -1
  • x²+2x= 14x+14-1
  • x² - 12x -13= 0

Roots of the quadratic equation are: -1 and 13.

So the integers pairs are: -1, 1 and 13, 15

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A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection ac
7nadin3 [17]

Answer:

the answe is d

Step-by-step explanation:

ye

3 0
3 years ago
At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more
I am Lyosha [343]

Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{10} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{9} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{8}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{7}

= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

4 0
3 years ago
|x|, if x=10; .3; 0; −2.7; −9
alekssr [168]

Answer:

For \left | x \right | we will have positive values only.

\left | -2.7 |\right =2.7

\left | -9 |\right =9

Rest are positive so will give positive values out of the modulus function.

Step-by-step explanation:

The absolute value of any number is its positive value only.

As for example (-2.7) and (2.7) both are having equal distance from 0 in a number line, one on the left other on the right side of the number line but are equidistant from 0.

So absolute value of a number is its distance on number line from reference point 0.

One by one we will work with all of our question.

\left | 10 |\right =10

\left | 0.3 |\right =0.3

\left | 0 |\right =0

\left | -2.7 |\right =2.7

\left | -9 |\right =9

So we have to take the positive number out of the modulus function that is also called absolute value.

5 0
3 years ago
37-(y-19)=2y this is a problom from rsm
ankoles [38]

Answer:

y = 56/3

Step-by-step explanation:

Distribute:

37 - (y - 19) = 2y

37 - y + 19 = 2y

Add the numbers:

37 - y + 19 = 2y

56 - y = 2y

Rearrange the terms:

56 - y = 2y

-y + 56 = 2y

Solution:

y = 56/3

8 0
2 years ago
K= m-q/c solve for m
krok68 [10]
Add q/c to the side with k and get q/c-k=m
5 0
3 years ago
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