Find the dimension of a rectangle whose width is 9 miles less than its length and whose area is 90 square miles
1 answer:
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7x² = 9 + x Subtract x from both sides
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula
a = 7 , b = -1 , c = -9
x =
Plug in the a, b, and c values
x =
Cancel out the double negative
x =
Square -1
x =
Multiply 7 and -9
x =
Multiply -4 and -63
x =
Multiply 2 and 7
x =
Add 1 and 252
x =
Split up the 
x =
The approximate square root of 253 is <span>15.905973.
</span>x ≈
Add and subtract
x ≈
Divide
x ≈
Round to the nearest hundredth
x ≈
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</span>
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula
a = 7 , b = -1 , c = -9
x =
x =
x =
x =
x =
x =
x =
x =
x =
The approximate square root of 253 is <span>15.905973.
</span>x ≈
x ≈
x ≈
x ≈
<span>
</span>