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slamgirl [31]
3 years ago
12

Write one pair of brackets in this calculation so that the answer is correct. 5 + 2 × 7 – 4 = 11

Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

Answer:

5+2*(7-4) =11

Step-by-step explanation:

This expression was kind of trial and error for me seeing as I'm not really good at logic, but this is pretty basic. There are three possible places the parentheses can be placed (assuming each pair holds 2 terms);

(5+2)*7-4\\5+(2*7)-4\\5+2*(7-4)

The answer to the first expression would be 45, which is not equal to 11.

The answer to the second expression would be 15, which is also not equal to 11.

The answer to the last expression is 11, so that is the correct answer.

Hope this helped :D

- Shay

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A) Use the definition of Laplace transform to find L{f }. (Do the integrals.) For what values of s is L{f } defined?f(t) = (2t+1
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For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

As given in the question,

Given function is equal to :

f(t) = 2t + 1

Simplify the given function using definition of Laplace transform we have,

L(f(t))s = \int\limits^\infty_0 {f(t)e^{-st} } \, dt

          =  \int\limits^\infty_0[2t +1] e^{-st} dt

          = 2\int\limits^\infty_0 te^{-st} + \int\limits^\infty_0e^{-st} dt

         = 2 L(t) + L(1)

L(1) = \int\limits^\infty_0e^{-st} dt

     = (-1/s) ( 0 -1 )

     = 1/s , ( s >  0)

2L ( t ) = 2\int\limits^\infty_0 te^{-st}

        =  2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]

        =  2/ s²

Now ,

L(f(t))s = 2 L(t) + L(1)

          = 2/ s² + 1/s

Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

Learn more about Laplace transform here

brainly.com/question/14487937

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