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erica [24]
3 years ago
12

In 1980, wind turbines in Europe generated about 5 gigawatt-hours of energy. Over the next 15 years, the amount of energy increa

sed about 59% (each year). How many gigawatt-hours were generated?
Mathematics
1 answer:
Zinaida [17]3 years ago
3 0
Well the equation could be, f(x)=5(1.59)^15
which would equal 5247
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What is the slope of the line?
Anarel [89]

Answer:

-3/4

Step-by-step explanation:

5 0
3 years ago
Write the coordinate of the vertices after a translation 8 units left and 13 units down. S(0,10). T(8,10) U(1,5)
Paha777 [63]

Answer:

S(-8,-3), T(0, -3), and U(-7, -8)

Step-by-step explanation:

for all of the coordinates, you would subtract 8 from their X-values, and subtract 13 from their Y-values.

6 0
3 years ago
Someone please help and thx
gogolik [260]

Answer:

  60 + 70n ≤ 200

Step-by-step explanation:

Since the $200 is a maximum, only inequalities with "≤ 200" make any sense in this context.

Since the unit rate for training sessins is $70, only expressions containing 70n make any sense in this context.

The only inequaity that makes any sense in this context is ...

  60 + 70n ≤ 200

5 0
4 years ago
A Ferris Wheel 22.0m in diameter rotates once every 12.5s. What is the ratio of a persons apperenet weight to her real weight (a
AnnZ [28]
  <span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed: 
a = omega^2*r 

omega and r in terms of given data: 
omega = 2*Pi/T 
r = d/2 

Thus: 
a = 2*Pi^2*d/T^2 

What forces cause this acceleration for the passenger, at either top or bottom? 

At top (acceleration is downward): 
Weight (m*g): downward 
Normal force (Ntop): upward 

Thus Newton's 2nd law reads: 
m*g - Ntop = m*a 

At top (acceleration is upward): 
Weight (m*g): downward 
Normal force (Nbottom): upward 

Thus Newton's 2nd law reads: 
Nbottom - m*g = m*a 

Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame: 
Ntop = m*(g - a) 
Nbottom = m*(g + a) 


Substitute a: 
Ntop = m*(g - 2*Pi^2*d/T^2) 
Nbottom = m*(g + 2*Pi^2*d/T^2) 

We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground): 
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g) 
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g) 

Simplify: 
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2) 
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2) 

Data: 
d:=22 m; T:=12.5 sec; g:=9.8 N/kg; 

Results: 
Ntop/(m*g) = 71.64%...she feels "light" 
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
7 0
4 years ago
Read 2 more answers
In your own words, explain when a quadratic equation will have no real
zubka84 [21]

Answer:

If a quadratic function is not discriminating at 0, it does not have any real roots and it does not intersect the x-axis in the parabola it serves.

Step-by-step explanation:

The equation has no true solution if the discriminant is less than 0.

3 0
3 years ago
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