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aksik [14]
3 years ago
9

A bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty. Find the

probability that the red tokens are drawn consecutively.
Mathematics
1 answer:
disa [49]3 years ago
4 0

Answer:

Therefore, the probability is P=1/84.

Step-by-step explanation:

We have a  bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty.

We conclude that in a bag have 9 tokens.  

We calculate the probability that the red tokens are drawn consecutively.

We calculate the number of possible combinations:

C_3^9=\frac{9!}{3!(9-3)!}=84\\\\

Number of favorable combinations is 1.

Therefore, the probability is P=1/84.

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100%/20%=5%

5×16=80

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Carmen spent a total of $60 at the grocery store. of this amount, she spent $57 on fruit. What percentage of the total did she s
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Multiply. Write the product as one power. a to the 8th power x a to the 5th power.
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Answer:

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4 0
2 years ago
A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a random
Zielflug [23.3K]

Answer: The 95% confidence interval for the mean of x is (94.08, 101.92) .

Step-by-step explanation:

We are given that ,

A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12.

i.e. \sigma= 12

Also, it is given that , Sample mean \overline{x}=98 having sample size : n= 36

For 95% confidence ,

Significance level : \alpha=1-0.95=0.05

By using the z-value table , the two-tailed critical value for 95% Confidence interval :

z_{\alpha/2}=z_{0.025}=1.96

We know that the confidence interval for unknown population mean(\mu) is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = Sample mean

\sigma = Population standard deviation

z_{\alpha/2} = Critical z-value.

Substitute all the given values, then the required confidence interval will be :

98\pm (1.96)\dfrac{12}{\sqrt{36}}

=98\pm (1.96)\dfrac{12}{6}

=98\pm (1.96)(2)

=98\pm 3.92=(98-3.92,\ 98+3.92)\\\\=( 94.08,\ 101.92)

Therefore, the 95% confidence interval for the mean of x is (94.08, 101.92) .

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3 years ago
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