Question

1. Find p(-3) if p(x) = 4x3 - 5x2 + 7x - 10

Answer 1

Answer:

1) -184

2) 13$(m^{4}) ^{2}$-3($m^{4}$)+4

Step-by-step explanation:

For problem number 1, Let's start by substituting all the x's for -3

So the equation will look like

p(-3)=$4(-3)^{3}$-$5(-3)^{2}$+7(-3)-10

Now, lets simplify by solving the exponents

First we'll do $-3^{3}$ which equals -27

Now we'll do $-3^{2}$ which equals 9

So now our equation looks like

p(-3)=4(-27)-5(9)+7(-3)-10

Now, we are going to multiply all these numbers

First 4(-27) which equals -108

Now -5(9) which equals -45

And finally 7(-3) which equals -21

Now our equation looks like

p(-3)= -108-45-21-10

Now we can solve

-108-45-21-10=-184