It lies between -3 and -4.
An integer is any whole number, positive or negative.
You would expand becausee it isn't equal to anything
(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one
so
for the 3rd power
a=x
b=3
=
Answer:
The sum of two numbers is 14 and their difference is 10
Step-by-step explanation:
"2 numbers (x and y)
x+y = 14
and x-y + 10
If you each equation by positive 2, one gets 2x+2y = 28 and 2x-2y = 20
The 'y-terms' cancel out or equal zero when adding, so 4x = 48, divide by 4 on each side and x or the first number equals 12.
Plug 12 back into the equation for 'x' and subtract 12 on both sides so that y=2
The difference of 12-2=10 and the addition of 12 and 2 equals 14"
hopes this helps
Answer:
56.842 km/hr
0.947 km / min
15.789 m/s
Step-by-step explanation:
speed = distance / time
let's assume your teacher wants it in km/ hr
28.5 minutes = ? hours
60 minutes = 1 hour
we can multiply both sides of 60 minutes = 1 hour by 28.5/60 to get 28.5 minutes = 28.5/60 hours
distance = 27 km
27 km / (28.5/60) hours = 56.842 km/hr
in km / minute
27 km / 28.5 minutes = 0.947 km / min
in meters/second:
1 minute = 60 seconds
28.5 minutes = ? seconds
we can multiply both sides of the first equation by 28.5 to get
28.5 minutes = 1710 seconds
27 km = ? meters
1 km = 1000 meters
we can multiply both sides of the second equation by 27 to get
27km = 27000 meters
27000 meters / 1710 seconds = 15.789 m/s
Answer: I’ll give you an example of how to do it by solving number 9 - h^2 + 8h + 16
Step-by-step explanation:
Step 1: Find two numbers that when you multiply them it gives you the first term’s coefficient multiplied by the last term’s coefficient (1x16 = 16) and when you add them it gives you the second term’s coefficient (8). The numbers in this case are positive 4 and positive 4.
Step 2: Create two parenthesis with the letter accompanied by the numbers. (h + 4)•(h+4). And that’s how you factor.
In case the first term is elevated to the third you will have to take out GCF (greatest common factor) first. If the numbers are too high like in the exercise number 15 you can also take out GCF and it will make it a lot easier to solve. Sometimes what you write on the parenthesis in the step 2 can be simplified, if that’s so then you would have to do it in order to get the correct answer.
Hope this helps you.
