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2 years ago

Y+8=0(x-6) Isolate y slope intercept (y=Mx+b)

Mathematics

2 answers:

emmainna [20.7K]2 years ago

4 0

Answer:

y=0

Step-by-step explanation:

Y+8=0(x-6) <-- point slope to slope int.

slope=0

The point is (6,-8)

y=0

musickatia [10]2 years ago

4 0

Answer:

Y = 0(x - 6) - 8

Step-by-step explanation:

You use the magic bridge to bring the 8 over to the other side of the equation and change it's sign from negative(-) to positive(+)

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siniylev [52]

184.2 is the answer to 4 significant figure

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An object with a mass of 4 kg is hanging from an axle with a radius of 36 cm. if the wheel attached to the axle has a radius of

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The answer is of course 78cm

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3 years ago

Following the lead of the National Wildlife Federation, the Department of the Interior of a South American country began to reco

chubhunter [2.5K]

Answer:

After 2009 the quality of the forests in this country improving.

Step-by-step explanation:

Consider the provided function.

$f(t) = \frac{1}{3}t^3-\frac{5}{2}t^2 + 80$

$f'(t) = t^2-5t$

Substitute f'(t)=0.

$t^2-5t=0$

$t(t-5)=0$

$t=0\ or\ t=5$

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The test interval are (0,5) and (5,10)

For (0 < t < 5) the value of $f'(t)$

For (5 < t < 10) the value of $f'(t) >0$

Hence, the function is increasing from (5,10).

t = 0 corresponds to 2004.

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3 years ago

The perimeter cf a rectangle i: 56 inches" the ratio of the length of the width is 6 : 1. Find the length and the width.

sergejj [24]

Answer: Length = 24; width =4

Step-by-step explanation

Since the ratio of the length to width is 6:1

Let the length be represented as 6x

And the width be = x

Such that that the Perimeter of the rectangle which is

Perimeter = 2(length + width) becomes

56 = 2(6x + x)

56/2 = 6x+x

28 = 7x

x = 4

Width = 4

Length = 6x= 6 x 4 = 24

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2 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

2 years ago