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makvit [3.9K]
3 years ago
8

Pleaaaase hellp me will mark u brainly for both answers!!! Thank u if u do really appreciate it.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

1. Option A is correct (A = length x width)

2. Option B is correct ( A = base x height/2)

Hope this helps

:)

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ANSWER ANY PART YOU KNOW!! (you don't have to answer all)
jolli1 [7]

Answer:

a)2*(15-s) mi

b)30mi

c) 30 mi

Step-by-step explanation:

6 0
3 years ago
Help helphelpherllplpeleplpglhler
IRINA_888 [86]
1.) 10² + 4 · (6 + 3) - (27 ÷ 9) - 6 = 127 
For these types of questions, try to think of it like, well since the last number is negative 6, let me try to get everything before it to equal 133 so it will end up being 127. :)

2.) ( \frac{3}{5}  -  \frac{1}{2} ) ÷ \frac{1}{2} + 1.6·(0.3 + 0.42)
= 1/10 ÷ 1/2 + 1.6 · (0.72)
= 1/5 + 1.152
= 1.352
Remember that dividing a fraction by a fraction is like multiplying the coefficient of the second one to the original one.

3.) 15 · 1/2 ÷ 3/4
Remember that product is multiplication and quotient is division.

4.) \frac{(54 \frac{3}{10} - 11 \frac{7}{10}) }{3}
Remember that difference is subtraction and separating into three parts is like dividing it into three parts.


Hope this helped and ask me for further explanation! ^-^
5 0
4 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm.
Gre4nikov [31]

a. Find the probability that an individual distance is greater than 214.30 cm

We find for the value of z score using the formula:

z = (x – u) / s

z = (214.30 – 205) / 8.3

z = 1.12

Since we are looking for x > 214.30 cm, we use the right tailed test to find for P at z = 1.12 from the tables:

P = 0.1314

 

b. Find the probability that the mean for 20 randomly selected distances is greater than 202.80 cm

We find for the value of z score using the formula:

z = (x – u) / s

z = (202.80 – 205) / 8.3

z = -0.265

Since we are looking for x > 202.80 cm, we use the right tailed test to find for P at z = -0.265 from the tables:

P = 0.6045

 

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

I believe this is because we are given the population standard deviation sigma rather than the sample standard deviation. So we can use the z test.

7 0
3 years ago
If the rule of the function is "multiply by 2 then add 3" and the input value is -2, what is the output value?
miv72 [106K]
The equation would be 2x+3 so when you plug it in it's 2(-2)+3 which simplify to -4+3 which is -1
5 0
3 years ago
A 1,300 kg car moving at 20 m/s and a 900 kg car moving at 15 m/a in precisely opposite directions crash head on. If we consider
Dmitry_Shevchenko [17]

Answer:

17.96m/s

Step-by-step explanation:

Based on law of conservation of momentum;

m1u1 +m2u2 =(m1+m2)v

v is the velocities of the car after impact

Substitute the given values

1300(20)+900(15) = (1300+900)v

26000 + 13500 = 2200v

39500 = 2200v

v = 39500/2200

v = 17.96m/s

Hence the speed of the cars after impact is 17.96m/s

5 0
3 years ago
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