One of the limitation of the social media marketing is the risk of negative comments that can hamper the marketing strategy and certainly hamper the sales.
<h3>What is marketing?</h3>
Marketing can be defined as the advertising of the services or products into the market for making the end user aware about the product. There are various marketing tricks that can help in increasing the sales of the products or services.
Learn more about marketing, here:
brainly.com/question/13414268
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Answer:
check your app permissions it may be blocking them or try resetting the app
Answer:
A compiled language is a programming language whose implementations are typically compilers and not interpreters. In this language, once the program is compiled it is expressed in the instructions of the target machine. There are at least two steps to get from source code to execution. While, an interpreted language is a programming language whose implementations execute instructions directly and freely, without previously compiling a program into machine-language instructions. While in this language, the instructions are not directly executed by the target machine. There is only one step to get from source code to execution.
I hope this helps.
Answer:
ASK
Explanation:
The correct answer is ASK which denotes Amplitude Shift Keying. This is essentially a type of amplitude modulation which represents the binary data that comes varied forms right in the amplitude of a signal.
Now the reason why It is the most susceptible technique to noise is due to the fact that between frequency, phase & amplitude, amplitude is the one that is most susceptible to being affected by noise when compared to the other two.
import java.util.Scanner;
public class JavaApplication70 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Input a String:");
String txt = scan.nextLine();
System.out.println("Input an integer:");
int num = scan.nextInt();
String newTxt = "";
int w = 0;
for (int i = txt.length()-1; i >= 0; i--){
char c = txt.charAt(i);
while (w < num){
newTxt += c;
w++;
}
w = 0;
}
System.out.println(newTxt);
}
}
I hope this helps!
