Question

Create a 4x5 matrix with ones everywhere and zeros on the last row.

Answer 1

Answer:

#include <iostream>

using namespace std;

int main() {

   int a[4][5];//declaring a matrix of 4 rows and 5 columns.

   for(int i=0;i<4;i++)

   {

       for(int j=0;j<5;j++)

       {

           if(i==3)//initializing last row as 0.

           {

               a[i][j]=0;

           }

           else//initializing last row as 1.

           {

               a[i][j]=1;

           }

       }

   }

   for(int i=0;i<4;i++)

   {

       for(int j=0;j<5;j++)

       cout<<a[i][j]<<" ";//printing the matrix.

       cout<<endl;

   }

return 0;

}

Output:-

1 1 1 1 1  

1 1 1 1 1  

1 1 1 1 1  

0 0 0 0 0

Explanation:

I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.