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Naddika [18.5K]
3 years ago
15

line k has a slope of -5. line j is perpendicular to line k and passes though the point (5,9) create the equation for line j

Mathematics
1 answer:
Anna71 [15]3 years ago
3 0

Answer:

y = 1/5x + 8

Step-by-step explanation:

The first thing you should know is that the slope of a perpendicular line is the opposite reciprocal. So, the slope of line j is 1/5. This is your current equation: y=1/5x + b. Plug in your coordinate to the equation, it should look like this: 9=1/5(5)+ b. 1/5 times 5 equals 1, so this is what it should look like: 9=1 + b. Subtract 1 from both sides to get 8 = b. Go back to your original equation and plug in 8 to b. This is your final equation: y = 1/5x + 8. Hope this helped!

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1) To find x we are going to use the Pythagorean equation:
 x= \sqrt{a^{2}+b^{2}  }
where 
a and b are the legs of our triangle. For our picture we can infer that a=10 and b=8, so lets replace those values in our equation to find x:
x= \sqrt{10^{2}+8^{2}}
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2) To find y we are going to use the trigonometric function tangent. Remember that tan(y)= \frac{opposite}{adjacent}. We know that the opposite side of our angle y is 8, and its adjacent side is 10, so lets replace those values in our tangent function to find y:
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We can conclude that the measure of angle z is 51.34°


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