F(3)=2(3)^2=1 would be 19
Answer:
4(3n+2) or 12n+8
Step-by-step explanation:
Given expression is:

The numerator of the fraction will be multiplied with 9n^2- 4
So, Multiplication will give us:

We can simplify the expression before multiplication.
The numerator will be broken down using the formula:
![a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}](https://tex.z-dn.net/?f=a%5E2%20-%20b%5E2%20%3D%20%28a%2Bb%29%28a-b%29%5C%5CSo%2C%5C%5C%3D%20%5Cfrac%7B8%5B%283n%29%5E2%20-%20%282%29%5E2%5D%7D%7B6n-4%7D%5C%5C%20%3D%20%5Cfrac%7B8%283n-2%29%283n%2B2%29%7D%7B6n-4%7D)
We can take 2 as common factor from denominator

Hence the product is 4(3n+2) or 12n+8 ..
The awnser is 145
(50 divided 2) = 25
5 to the power of 3= 125
-5
=145
B) should be your answer
The first one (the one given), is 6 "points" (forgot what it's called sorry) from 0 on all sides. To dilate it 1/3, divide 6 and 3
6/3 = 2
The one's that have points that land on points with 2 in it is B
so B is your best answer
hope this helps