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Furkat [3]
3 years ago
6

In △XYZ , XZ=9 , YZ=4 , and XY=7 .

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

A=6\sqrt{5}\ units^2

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.  

so

A=\sqrt{s(s-a)(s-b)(s-c)}

where

a, b and c are the length sides of triangle

s is the semi-perimeter of triangle

we have

a=9\ units,b=4\ units,c=7\ units

Find the semi-perimeter s  

s=\frac{9+4+7}{2}=10\ units

Find the area of triangle

A=\sqrt{10(10-9)(10-4)(10-7)}

A=\sqrt{10(1)(6)(3)}

A=\sqrt{180}\ units^2

Simplify

A=6\sqrt{5}\ units^2

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Three functions are given below: f(x), g(x), and h(x). Explain how to find the axis of symmetry for each function, and rank the
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Answer:

1. x=8 is the line of symmetry for f(x) = -4(x − 8)2 + 3

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here, we need to complete the squares,

g(x) = 3x2 + 12x + 15

g(x) = 3(x^2+4x+5)

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So setting x=-2 will anihilate or cancel the squared term, therefore

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5 0
3 years ago
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
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1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

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