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kobusy [5.1K]
3 years ago
14

Help needed please!!

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0
^^deserves brainliest^^
Alchen [17]3 years ago
7 0
Add f and g together:

4x + 6 + 9x +9 ( Combine like terms)

13x+15

Now replace x with -6 and solve:
13(-6) +15 = -78 +15 = -63

The answer is -63
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What is the value of the expression 18-2×(4 +3)
klio [65]
 The answer is 4 because of pemdas

7 0
3 years ago
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Last Month, Levi had written 125 words of his book. This month,he is up to 12,580 words. About how many times more words has he
VladimirAG [237]

Answer:

He has written about 100 times as many words.

Step-by-step explanation:

In order to find this, we first need to find the number that he has written this month. In order to do so, we need to subtract the previous month from the current total.

12,580 - 125 = 12,455

Now that we have that number, we can divide it by the previous month to see how many times more words he wrote in the second month.

12,455/125 = 99.64 times more, or rounded, about 100 times more.

8 0
3 years ago
X + 2y = 5, x - Зу = 7 What is the value of the system determinant?​
Whitepunk [10]

Step-by-step explanation:

The solution is on the script

3 0
3 years ago
Struggling lol. Any help would be appreciated!
Alekssandra [29.7K]

Answer:

Heptagon = 84 ft²

Octagon  = 186 yd²

Triangle = 48√3 m²

Step-by-step explanation:

\textsf{area of a regular polygon}=\dfrac12ap

where:

  • a = length of apothem
  • p = perimeter

<u>Heptagon</u>

a = 5.0 ft

p = 33.6 ft

⇒ area = 1/2 x 5.0 x 33.6 = 84 ft²

<u>Octagon</u>

a = 7.5 yd

p = 8 x 6.2 = 49.6 yd

⇒ area = 1/2 x 7.5 x 49.6 = 186 yd²

<u>Triangle</u>

Formula for the apothem of an equilateral triangle :

a=\dfrac{s}{2\sqrt{3}}  where s = side length

a = 4, so:

4=\dfrac{s}{2\sqrt{3}}

\implies 8\sqrt{3}=s

Now we know the side length, we can calculate the perimeter (p):

p = 3 x 8√3 = 24√3

⇒ area = 1/2 x 4 x 24√3 = 48√3 m²

8 0
2 years ago
How to find if an equation is parallel perpendicular or neither?
iren [92.7K]
Look at the gradient of both the equations (the x multiplier, usually known as m), and there are a couple of rules:

Parallel: The gradients are identical
Perpendicular: Look at the gradients as fractions. To get the perpendicular to a gradient you flip the fraction and change the sign. If this is the case for the two gradients, then they are perpendicular.
6 0
3 years ago
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