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lana66690 [7]
3 years ago
13

What is the variable of p and k explain please

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0
For the P=-4
what you do is subtracting 6 to the 38 you will have -8p=32 then you will divide-8 to both sides and your answer will be p=-4
check 6-8(-4)=38
6+32=38
38=38


i got K=5.6
what you do is add 13 to the 15 and you will have 28=5k then you will divide 5 to both sides and you will have k=5.6
check 15=5(5.6)-13
15=28-13
15=15
You might be interested in
WILL MARK BRAINLIEST!! The coordinates of the vertices of quadrilateral JKLM are J(-3,2), K(4,-1), L(2,-5) and M(-5,-2). Find th
irinina [24]
Answer:
JKLM is a parallelogram
Explanation:
The slope m of a line through two points (x1,y1) and (x2,y2)is given by the formula:
m=Δy/Δx=y2-y1/x2-x1
So the slopes of the sides of our quadrilateral are:
mJK=(−1)−24−(−3)=−37
mKL=(−5)−(−1)2−4=2
mLM=(−2)−(−5)−5−2=−37
mMJ=2−(−2)(−3)−(−5)=2
So JK is parallel to LM and KL is parallel to MJ
So JKLM is a parallelogram.
5 0
2 years ago
Find the area of a triangle with a =33, b =51, and c =42.
PolarNik [594]

Answer:

d. 690.1 units²

Step-by-step explanation:

1. You can use the Heron's formula to calculate the area of the triangle, which is:

K=\sqrt{s(s-a)(s-b)(s-c)}

Where:

s=\frac{a+b+c}{2}

2. Calculate s:

s=\frac{33+51+42}{2}\\s=63

3. Substitute values into the formula shown above and calculate the area, as following:

K=\sqrt{63(63-33)(63-51)(63-42)}\\K=690.1units^{2}

4. Therefore, the area is 690.1 units².

4 0
3 years ago
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
2 years ago
A number x is more than -6 and at most 8
Nataly [62]
-6 < x (less than or equal to) 8
8 0
2 years ago
Solve for X: 5x + 15 = 28
rjkz [21]
-15 both sides and then it’s will be
5x = 13 then u divide both sides over 5 and the answer will be ( X=2.6 )
4 0
2 years ago
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