Iron reacts with oxygen in the air to make rust.

During the growth stage of the industry life cycle, ______ increases rapidly.

ololo11 [35]

During the growth stage of the industry life cycle, imitation the cost of production increases rapidly.

<h3>What happens during growth stage?</h3>

The growth stage serves as the stage whereby the product's sales begin to increase dramatically .

It is a stage whereby product experiences high demand, and imitation the cost of production increases rapidly.

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3 0

2 years ago

Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o

Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

Carbon (C): 47.37 grams
Hydrogen (H): 10.59 grams
Oxygen (O): 42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

Carbon (C): $\frac{47.37 grams}{12 \frac{g}{mole} }$ = 3.95 moles
Hydrogen (H): $\frac{10.59 grams}{1 \frac{g}{mole} }$ = 10.59 moles
Oxygen (O): $\frac{42.04 grams}{16 \frac{g}{mole} }$ = 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Carbon (C): $\frac{3.95 moles}{2.63 moles }$ = 1.5
Hydrogen (H): $\frac{10.59 moles}{2.63 moles }$ = 4
Oxygen (O): $\frac{2.63 moles}{2.63 moles }$ = 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

Carbon (C): 1.5× 2= 3
Hydrogen (H): 4× 2= 8
Oxygen (O): 1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

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3 0

2 years ago

Why does having a high first ionization energy and high electronegativity cause a nonmetal to be very reactive?.

Elena-2011 [213]

There in an increase in reactivity because the nonmetals want to hold on to their electrons.

<h3>Reactivity</h3>

With less electronegativity, there is also less ionization energy. For metals, it is easier to lose the electrons, hence the metal becomes more reactive because it uses less energy.

For nonmetals, they are gain electrons and not lose them. Thus, an increase in electronegativity and ionization energy means an increase in reactivity because the nonmetals want to hold on to their electrons.

Find out more on reactivity at: brainly.com/question/17141109

6 0

2 years ago

Send me a email explaining why my product is late and what your are doing to solve it

aalyn [17]

do you want a fr answer?

7 0

3 years ago

Your credit limit is $1,500. You don’t pay your card off each month like you should. What is the max you can safely charge on th

IgorLugansk [536]

I would say about 50 or 100 dollars but i advice you pay off your card so you can have your credit limit back and dont make your credit score worse

4 0

3 years ago

Read 2 more answers