Ask question

Ask question

All categories

3 years ago

10

The sum of two numbers is 60. The greater number is 6 more than the smaller number. Which equation can be used to solve for the

smaller number?
x + (x + 6) = 60
x − (x + 6) = 60
x(x + 6) = 60
x(x− 6) = 60

2 answers:

yuradex [85]3 years ago

6 0

A is the answer for that

Maslowich3 years ago

6 0

The answer to your problem is X+(X+6)=60

You might be interested in

Owen is fishing from a dock he starts with the bait 2 feet below the surface he reels out the boat 19 feet then reels it back in

Hatshy [7]

Answer:

The bait is 14 feet below the water surface

Step-by-step explanation:

Here, we want to know the final position of the bait relative to the surface of the water.

Firstly, he starts with the bait at 2 feet below the water surface. The reels out the bait a further 19 feet, the new position of the bait relative to the water surface will be 2 + 19 = 21 feet

Now, he reels the bait back by 7 feet.

Thus, the new depth of the bait relative to the water surface will be 21-7 = 14 feet

4 0

3 years ago

What number(s) have the absolute value of 7? Why? (Must explain to receive credit)

Liula [17]

Answer:

Why is | 7 | the absolute value of the number 7?

The absolute value of a number is how far away the number is from zero. The absolute value is ALWAYS positive.

What is the absolute value of -7?

The negative version of the number is also | 7 |

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How to graph a standard form equation

Svetach [21]

This formule is
ax + bx = c
ex
y =2x - 4
-2x + y = -4
-( -2x + y = -4)
2x - y = 4

5 0

3 years ago

diamong [38]

Answer:

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is $I$ .

We have joined the incenter $I$ to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for <em>area</em> of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$

So, radius of circle = $10-5\sqrt2$

8 0

3 years ago

Can anyone show me the steps in order solve this problem

STatiana [176]

M∠A = 42° [isosceles triangle]

m∠B = 180 - 42 - 42 = 96° [in a triangle, the three interior angles always add to 180°]

m∠C = 180 - 96 - (x+12)
m∠C = 84 - x - 12
m∠C = 72 - x

2x+9 + 3x-1 + 72-x = 180
4x + 80 = 180
4x = 180 - 80
4x = 100
x = 100/4
x = 25

m∠C = 72 - x = 72 - 25 = 47°

<span>I hope this helped</span>

8 0

3 years ago