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juin [17]
4 years ago
7

Can someone please HELP me on how to do this

Mathematics
1 answer:
frutty [35]4 years ago
7 0

Answer:

4)x= g-c

5)x =u+k

6)x = g-c

7)a=\frac{k}{u}

8)x= \frac{g}{c}

9)a=\frac{4}{12m}

10)x= \frac{2c+3}{3}

11)a=\frac{n+p}{m}

12)a= \frac{ub}{k}

13)a= d -r + c

14)x=\frac{np}{m}

Step-by-step explanation:

4) g= c+x

x= g-c

5) u=x-k

x =u+k

6)g = c+x

x = g-c

7) u=\frac{k}{a} \\\\a=\frac{k}{u}

8) g=xc

x= \frac{g}{c}

9) 12am = 4

a=\frac{4}{12m}

10)-3x+2c = -3

2c = -3 +3x

2c +3 = 3x

x= \frac{2c+3}{3}

11) am= n+p

a=\frac{n+p}{m}

12)u = \frac{ak}{b} \\\\u*b = ak\\\\a= \frac{ub}{k}

13)a-c = d-r

a= d -r + c

14)xm= np

x=\frac{np}{m}

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What is the GCF of 48m5n and 81m2n2
Art [367]
48m^5n: 3*2^4*m^5n

81m^2n^2: 3^4m^2n^2

GCF: 3*m^2n
8 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
Nora's leaf collection consisted of 150 leaves by August. By december , her collection had grown to 177 leaves. How much did her
Elza [17]
Answer=18%

177/150=1.18

1.18=118%

118%-100%=18%

___________________________
another way to solve the equation...

  150     177
_____=_____
100%      x

Cross Multiply
150x=17700
divide both sides by 150
x=118%

118%-100%=18%
4 0
3 years ago
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NNADVOKAT [17]
The answers to the questions

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siniylev [52]

Answer:

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50% of choosing 8th grade boy

Step-by-step explanation:

4 0
3 years ago
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